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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
Friction is the correct answer.
The acceleration that Andrew experience during his ride is 3.6m/s²
The formula for calculating centripetal acceleration is expressed as:
a = v²/r
v is the speed
r is the radius
Given the following expression
v = 6m/s
r = 10m
Substitute the given parameters into the formula
a = 6²/10
a = 36/10
a = 3.6m/s²
Hence the acceleration that Andrew experience during his ride is 3.6m/s²
Learn more here: brainly.com/question/1268866
What Kepler's constant ? ? ! ?
The only constant in Kepler's laws is in the third one, where it says something to the
effect that (square of a body's period) / (cube of its distance from the central body)
is a constant.
That means it's a constant for multiple little ones orbiting the same central body.
But it's not the same constant for other central bodies.
It's one constant for the planets, asteroids, and comets orbiting the sun.
It's a different constant for the moon, TV satellites, weather satellites,
and military satellites orbiting the Earth.
Do you not understand how to solve for the answer?
