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3 years ago

You dribble a basketball while walking on a basketball court. List and describe at least 3

Physics

2 answers:

Airida [17]3 years ago

4 0

Answer:

1. You push on the ball and the ball pushes on your hand .

2. The ball hits the ground and the ground pushes back on the ball .

3. You walk on the ground with your feet and the ground pushes back on you.

Explanation:

stellarik [79]3 years ago

4 0

Answer:

1. Walking

2. Pushing the basketball with hand

3. Ball bouncing off the ground

Explanation:

As per Newton's third law of motion every action has an equal and opposite reaction. Looking at the given scenario following are the pairs of action-reaction forces:

1. Walking: When you walk, you apply action and push the ground and the ground pushes you back with the same force.

2. Pushing the basketball with hand: when you push the ball that is action, the ball also applies force on your hand which is the reaction.

3. Ball bouncing off the ground: When ball hits the ground, it applies force i.e. action and the ground pushes it back with the same force which is the reaction.

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A CD has to rotate under the readout-laser with a constant linear velocity of 1.25 m/s. If the laser is at a position 3.7 cm fro

Savatey [412]

Answer:N=322.53 rpm

Explanation:

Given

Linear velocity (v)=1.25 m/s

Position from center is 3.7 cm

we know

$v=\omega \times r$

$1.25\times 100=\omega \times 3.7$

$\omega =\frac{125}{3.7}=33.78$

and $\frac{2\pi N}{60}=\omega$

$N=\frac{\omega \times 60}{2\pi }$

$N=\frac{33.78\times 60}{2\pi }$

N=322.53 rpm

8 0

3 years ago

What minimum distance should you separate two sources emitting the same waves with wavelength 5mm in phase such that you obtain

Makovka662 [10]

To solve this problem we will apply the concept related to destructive interference (from the principle of superposition). This concept is understood as a superposition of two or more waves of identical or similar frequency that, when interfering, create a new wave pattern of less intensity (amplitude) at a point called a node. Mathematically it can be described as

$d = n \frac{\lambda}{2}$

Where,

d = Path difference

$\lambda$ = wavelength

n = Any integer which represent the number of repetition of the spectrum

In this question the distance between the two source will be minimum for the case of minimum path difference, then n= 1

$d = \frac{\lambda}{2}$

$d = \frac{5*10^{-3}}{2}$

$d = 2.5mm$

Therefore the minimum distance that should you separate two sources emitting the same waves is 2.5mm

8 0

3 years ago

A circular bird feeder 19.0 cm in radius has rotational inertia 0.130 kg·m2. It's suspended by a thin wire and is spinning slowl

soldi70 [24.7K]

Answer:

N₂=20.05 rpm

Explanation:

Given that

R= 19 cm

I=0.13 kg.m²

N₁ = 24.2 rpm

$\omega_1=\dfrac{2\pi \times 24.2}{60}\ rda/s$

ω₁= 2.5 rad/s

m= 173 g = 0.173 kg

v=1.2 m

Initial angular momentum L₁

L₁ = Iω₁ - m v r ( negative sign because bird coming opposite to motion of the wire motion)

Final linear momentum L₂

L₂= I₂ ω₂

I₂ = I + m r²

The is no any external torque that is why angular momentum will be conserve

L₁ = L₂

Iω₁ - m v r = I₂ ω₂

Iω₁ - m v r = ( I + m r²) ω₂

Now by putting the all values

Iω₁ - m v r = ( I + m r²) ω₂

0.13 x 2.5 - 0.173 x 1.2 x 0.19 = ( 0.13 + 0.173 x 0.19²) ω₂

0.325 - 0.0394 = 0.136 ω₂

ω₂ = 2.1 rad/s

$\omega_2=\dfrac{2\pi \times N_2}{60}$

N₂=20.05 rpm

3 0

3 years ago

A 2.0 kg particle moving along the z-axis experiences the

DochEvi [55]

At point x = 0, the particle accelerates. Since there will be change of velocity at that point. The the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.

Given that a 2.0 kg particle moving along the z-axis experiences the force shown in a given figure.

Force is the product of mass and acceleration. While acceleration is the rate of change of velocity. Both the force and acceleration are vector quantities. They have both magnitude and direction.

If the particle's velocity is 3.0 m/s at x = 0 m, that mean that the particle experience change of velocity at point x = 0. Since the the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.

Learn more here: brainly.com/question/20366032

6 0

3 years ago

A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a l

zalisa [80]

Answer:

Explanation:

Expression for time period of pendulum is given as follows

$T=2\pi\sqrt{\frac{l}{g} }$