5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH is mathematically given as
V=2.107mL
<h3>What is the volume of 5.50M NaOH?</h3>
Generally, the equation for Chemical Reaction is mathematically given as
CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O
Therefore
pka=-log(1.8*10{-5})
pKa=5-0.25527
pKa=4.3447
Hence
![pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7BCH3COO%7D%7BCH3COOH%7D%5C%5C%5C%5C0.75%3D4.7447%2Blog%5Cfrac%7B0.01564%2Bx%7D%7B0.01428-x%7D)
x=0.0115898
Volume of NaOH
V=0.0021072L
V=2.107mL
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Answer:
Supersaturated solution.
Explanation:
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In this case, according to the types of solution in terms of the relative amounts of solute and solvent, we can define a point called solubility at which the amount of solute is no longer dissolved in the solvent; thus, a value of solute/solvent less than the solubility is related to unsaturated solutions, equal to the solubility is related to the saturated solutions and more than the solubility to supersaturated solutions.
Thus, since solubility is temperature-dependent, at 30 °C the solubility of sodium chloride is 36.09 g per 100 mL of water; which means that, since the solution has 50 g of sodium chloride, more than 36.09 g, we infer this is a supersaturated solution.
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A molecule of hydrogen is formed by two hydrogen atoms, that is a fact.
How does it work? When two atoms, known as "diatomic" pair with another in a bond known non-polar covalent bonds. Where they equally share electrons. A Hydrogen atoms needs 1 more electrons to fill its first shell fully and have a full valence shell. So if two H's share their electrons, they'll both have a full V-Shell!
That's the basics of both the H-H bond and all the other diatomic bonds as well.
Number of moles is mathematically expressed as,
![\frac{\text{Weight of solute (g)}}{\text{gram molecular weight}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Ctext%7BWeight%20of%20solute%20%28g%29%7D%7D%7B%5Ctext%7Bgram%20molecular%20weight%7D%7D%20)
......(1)
Thus, for estimating number of moles, one need to know weight of solute and molecular weight.
Now, if one measure the volume of solid and density of solid is know, then one can employ following formula for estimating weight of solid:
Weight of solid = Volume of solid x Density
On substituting the obtained weight of solid in Eq. 1, one can obtain number of moles of solid.
It’s the nerves but I’m not 100% sure if I’m correct