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3 years ago

What kind of solution would you have if it contained 50 grams of sodium chloride in 100 mL of water at 30˚C?

Chemistry

1 answer:

Svetlanka [38]3 years ago

5 0

Answer:

Supersaturated solution.

Explanation:

Hello!

In this case, according to the types of solution in terms of the relative amounts of solute and solvent, we can define a point called solubility at which the amount of solute is no longer dissolved in the solvent; thus, a value of solute/solvent less than the solubility is related to unsaturated solutions, equal to the solubility is related to the saturated solutions and more than the solubility to supersaturated solutions.

Thus, since solubility is temperature-dependent, at 30 °C the solubility of sodium chloride is 36.09 g per 100 mL of water; which means that, since the solution has 50 g of sodium chloride, more than 36.09 g, we infer this is a supersaturated solution.

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Vanillin (used to flavour vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

Rudiy27

Answer:

The cost is $0.063.

Explanation:

First, we need to express the volume of the hangar in liters. We know that 1 ft³ = 28.31 L, so using proportions:

$5.0 \times 10^{7} ft^{3} .\frac{28.31L}{1ft^{3} } =1.4 \times 10^{9} L$

The amount of vanillin required would be:

$1.4 \times 10^{9} L.\frac{2.0\times 10^{-11}g }{1L} =0.028g$

Finally, the price for such amount of vanillin is:

$0.028g.\frac{ \textdollar 112}{50g}= \textdollar 0.063$

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3 years ago

Given 40 grams of magnesium. How many mole is this

Dahasolnce [82]

To determine the moles in 40 grams of magnesium, we need the atomic weight. This can easily be found on a periodic table. For this problem, let's use 24.305 grams/mole.

We are going to set up an equation to determine this problem. In this equation, we want all our units to cancel out except for 'moles.'

$\frac{40 g Mg}{1} x\frac{1 mole Mg}{24.305 g Mg}$

In this, we can see that the unit 'grams' will cancel out to leave us with moles.

In solving the equation, we determine that there are approximately 1.65 moles of Magnesium.

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3 years ago

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2 years ago

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harina [27]

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Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

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