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Nataly [62]
3 years ago
14

The corresponding sides of two similar rectangles are 14 ft and 8 ft. The area of the smaller rectangle is 57 ft2. To the neares

t whole number, what is the area of the larger rectangle? A. 175 ft2 B.150 ft2 C.100 ft2 D.200 ft2
Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0
C 100 ft2  need more characters sorry ashdashdasisncsijdhcfniuslfnxcm
djverab [1.8K]3 years ago
7 0
Is C.100 think tjat might help
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mihalych1998 [28]
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Write your answer as a while number
rusak2 [61]

Answer:

10 is your answer

Step-by-step explanation:

2×15/3

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liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71

By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
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Sedaia [141]

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                      = \sqrt{(3-1)^2+(5-3)^2}

                      = \sqrt{8}

                      = 2.83 units

Length of AD = \sqrt{(3-5)^2+(5-3)^2}

                      = \sqrt{8}

                      = 2.83 units

Length of BC = \sqrt{(1-3)^2+(3+1)^2}

                      = \sqrt{20}

                      = 4.47 units

Length of DC = \sqrt{(5-3)^2+(3+1)^2}

                       = \sqrt{20}

                       = 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

                                                 = 2.83 + 2.83 + 4.47 + 4.47

                                                = 14.6 units  

Option (B) is the answer.

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