How many triangles can be constructed with angles measuring 120°, 40°, and 10°? one more than one none

2 answers:

4 0

I might be wrong but i believe you can make more than one with those 3 angles. the 120 and 40 can make one and if angled right can make 2 and the 10 deg on one of the other angles lines would give you a 3rd.

Margaret [11]3 years ago

3 0

The interior angles of a triangle must sum to 180 degrees.

$\rm 120 + 40 + 10\ne180$

These angles do not sum to the proper amount. No triangle can be constructed using all three angles.

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∠A and ∠B are complementary angles. The measure of ∠A=4x° and the measure of ∠B=50°. Find m∠A. * i dont understand can someone h

jolli1 [7]

Answer:

m>a is 40

Step-by-step explanation:

4x + 50 = 90

4x = 40

x = 10

10*4 = 40

M>A = 40

3 0

3 years ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

Urn 1 = 2 red + 4 white = 6 chips
Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : $\frac{1}{3}$ (2 red from 6 chips(2/6=1/2))

For a white one is: $\frac{2}{3}$ (4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

In the first case the probability of taking a white one is of: $\frac{2}{5}$ = 40% ( 2 whites of 5 chips)
In the second case the probability of taking a white one is of: $\frac{1}{5}$ = 20% ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

$\frac{4}{6}$ x $\frac{2}{5}$ = $\frac{4}{15}$ = 26.66% ( $\frac{4}{6}$ the probability of taking a white chip from the urn 1, $\frac{2}{5}$ the probability of taking a white chip from urn two)

For the second case we multiply:

$\frac{1}{3}$ x $\frac{1}{5}$ = $\frac{1}{30}$ = .06% ( $\frac{1}{3}$ the probability of taking a red chip from the urn 1, $\frac{1}{5}$ the probability of taking a white chip from the urn two)