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3 years ago

How many triangles can be constructed with angles measuring 120°, 40°, and 10°? one more than one none

2 answers:

4 0

I might be wrong but i believe you can make more than one with those 3 angles. the 120 and 40 can make one and if angled right can make 2 and the 10 deg on one of the other angles lines would give you a 3rd.

Margaret [11]3 years ago

3 0

The interior angles of a triangle must sum to 180 degrees.

$\rm 120 + 40 + 10\ne180$

These angles do not sum to the proper amount. No triangle can be constructed using all three angles.

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Which number line represents the solution to the inequality 22 > 10x

S_A_V [24]

Answer:

$\large\boxed{x$

Step-by-step explanation:

$22>10x\qquad\text{divide both sides by 10}\\\\\dfrac{22}{10}>\dfrac{10x}{10}\\\\2.2>x\to\boxed{x$

<, > - open circle

≤, ≥ - closed circle

<, ≤ - draw the line to the left

>, ≥ - draw the line to the right

3 0

2 years ago

A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig

elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is $9000 ft^2$ then $9000=xy$

Step-by-step explanation:

• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.

• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)] by excluding the margin of top and bottom from the total height.

• To find the printed area of billboard calculations are given below:

$& 9000=xy$

$& y=\frac{9000}{x} \\ & A=(x-10)(y-6) \\ & A=xy-6x-10y+60 \\ & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\ & A=9060-6x-\frac{9000}{x} \\$

On taking the first order derivative of A

$A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)$

$& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\ & 6{{x}^{2}}=90000 \\ & x=\sqrt{15000} \\ & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\$

• Hence $x=10\sqrt{150}$ and $y=\frac{900}{\sqrt{150}}$

Learn More about Differentiation Here:

brainly.com/question/13012860

7 0

2 years ago

Read 2 more answers

Hey can you help me answer this question by giving me the answer?

Leto [7]

The value of f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Given a function f(x)=4-2x+6 $x^{2}$ .

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

f(a+h)== $4-2(a+h)+6(a+h)^{2}$

=4-2a-2h+6( $a^{2} +h^{2} +2ah$ )

=4-2a-2h+6 $a^{2} +6h^{2} +12ah$

= $6a^{2} +6h^{2}-2a-2h+12ah$

[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

= $(6a^{2} +6h^{2} -2a-2h+12ah)/h$

= $(6h^{2} -2h+12ah)/h$

=6h+12a-2.

Hence the value of function f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Learn more about function at brainly.com/question/10439235

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7 0

1 year ago

Which expression does the model represent?

Fed [463]

Answer:

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2 years ago

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Isis is 8 years younger than

meriva

Answer:

Step-by-step explanation:

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2 years ago