All categories

2 years ago

Can a ladybug be millimeters or centimeters???(which is most common)

Mathematics

1 answer:

Roman55 [17]2 years ago

8 0

The average ladybug is about 1 cm long, but it is more accurate to measure in millimeters.

You might be interested in

A jar contains 100 ounces of lemonade. A spout at the bottom of the jar is opened and the lemonade pours out at a rate of 10 oun

emmasim [6.3K]

Answer:

100 ounces(hope it help)

Step-by-step explanation:

because there is only 100 ounces in the jar.

4 0

3 years ago

PLZZ ANSWER THIS AS SOON AS POSSIBLE!!!!

alexandr402 [8]

Answer:

y = -9.3

if they are complementary it is 45 degrees

if they are supplementary it is 90 degrees

Step-by-step explanation:

-12.7 = y -3.4

-12.7 + 3.4 = y -3.4 + 3.4

-9.3 = y

complementary angles equal to 90 degrees

supplementary angles equal to 180 degrees

vertical angles have same degrees

so 90/2= 45

180/2 =90

3 0

2 years ago

Read 2 more answers

Number of subsets of B={p,q,r}

oksian1 [2.3K]

Answer:

Step-by-step explanation:

B = {p , q , r}

Number of subsets = $2^{n}$

Her, n is the number of elements in the set.

Number of subsets = 2³ = 8

3 0

2 years ago

HELP FAST FAST FAST PLSS

Ivan

Answer:

B. Distributive Property

Step-by-step explanation:

The distributive property tells us that a(b+c)=(a×b)+(a×c).

Same with the question.

9(16+20)=(9×16)+(9×20).

6 0

3 years ago

Read 2 more answers

The following table gives results from two groups of students who took a nonproctored test. Use a 0.01 significance level to tes

Nana76 [90]

Answer:

Original claim is $\mu_{1} =\mu_{2}$

Opposite claim is $\mu_{1} \neq \mu_{2}$

Null and alternative hypotheses:

$H_{0}:\mu_{1} = \mu_{2}$

$H_{1} : \mu_{1} \neq \mu_{2}$

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

$\bar{x_{1}}=70.29$

$Sx1=22.09$

$n_{1} = 30$

$\bar{x_{2}}=74.26$

$Sx2=18.15$

$n_{2} = 32$

$\mu_{1} \neq \mu_{2}$

Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

$t=-0.78$

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

6 0

2 years ago