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3 years ago

6

Please help me with this and please give me the right answer it’s due tommorow

1 answer:

NARA [144]3 years ago

5 0

First, look and compare at the decimal places in brackets ( ) .

A. (0).561 , (8).627 , (5).325 (wrong)

B. 4.(0)57, 4.(1)22, (5).008 (4.0.., 4.1.., 5.00..) least to greatest - (correct)

C. 1.(7)42 , 1.(5)58, 1.(6)71 - (wrong)

D. Greatest to least - (wrong)

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Every rational number is a

nordsb [41]

<em>Greetings from Brasil...</em>

a - whole number

FALSE

3/5, for example isnt a whole number

b. natural number

FALSE

0,457888..., for example isnt a natural number

c. integer

FALSE - like a

d. real number

TRUE

The set of real numbers contains the set of rational numbers

ℝ ⊃ ℚ

8 0

4 years ago

If you know please help me

MrRa [10]

Average rate of change of the function $=\frac{75}{2}$

Solution:

Given function: $f(x)=5(2)^{x}$ from x = 1 to x = 5

Substitute x = 1 and x = 5 in f(x).

$f(1)=5(2)^{1}=10$

$f(5)=5(2)^{5}=160$

Let us find the average rate of change of the function.

Average rate of change

$$=\frac{f(b)-f(a)}{b-a}$

Here a = 1 and b = 5.

$$=\frac{f(5)-f(1)}{5-1}$

Substitute f(5) and f(1).

$$=\frac{160-10}{4}$

$$=\frac{150}{4}$

$$=\frac{75}{2}$

Average rate of change of the function $=\frac{75}{2}$

4 0

3 years ago

mark is an auto dealer he sold a car and made a loss of 10% if his loss was $150000 A calculate how much he sold the car for B w

storchak [24]

Answer:

A. he sold the the car for 1350000

B. his cost price is 1500000

Step-by-step explanation:

A. 150000---> 10%

x-----> 90%

cross multiplication: x=150000×90/10=1350000

B. 10%( price) +90%(price)

1350000+150000=1500000

5 0

3 years ago

The weights of steers in a herd are distributed normally. The variance is 10,000 and the mean steer weight is 1400lbs. Find the

saw5 [17]

Answer:

$P(1539$

And we can find this probability using the normal standard table with this difference:

$P(1.39$

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(1539,1580)$

Where $\mu=1400$ and $\sigma=\sqrt{10000}= 100$

We are interested on this probability

$P(1539$

And we can solve the problem using the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(1539$

And we can find this probability using the normal standard table with this difference:

$P(1.39$

5 0

3 years ago

HELP ME!!!!!! GEOMETRY!!!!!!

Masja [62]

You need to divide 71 / 10.

4 0

3 years ago

Read 2 more answers