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Roman55 [17]
3 years ago
8

Which of the following equations are balanced?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

The only balanced equation is:

2KClO₃ → 2KCl + 3O₂

Explanation:

In reactant side: 6 atoms of O, 2 atoms of Cl and 2 atoms of K

In product side: 2 atoms of K and 2 atoms of Cl + 6 atoms of O

CO + 3H₂ → CH₃OH

In reactant side: 1 C, 1 O and 6 H

In product side: 1 C, 4 H and 1 O

PCl₃ + 2Cl₂ → PCl₅

In reactant side: 1 P, 7 Cl

In product side. 1 P, 5 Cl

Mg + N₂ → Mg₃N₂

In reactant side 1 Mg and 2 N

In product side 3 Mg and 2 N

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An organic compound absorbs strongly in the IR at 1687 cm1. Its 'H NMR spectrum consists of two signals, a singlet at 2.1 ppm an
tatuchka [14]

This question does not contain the structures of the molecules. The structures in Daylight SMILES format are:

I. C1=CC=CC=C1C(=O)C

II. C1=CC=CC=C1CC=O

III. C1=CC(C)=CC=C1C=O

IV. C1=CC=CC=C1CCC

V. C1=CC=CC=C1C(C)C

The structures are also attached

Answer:

The structure of compound IV is consistent with the information obtained analysis

Proposed structures for the ions with m/z values of 120, 105,77 and 43 are (also attached):

C1=CC=CC=C1C(=[OH0+])C |^1:7|

C1C([CH0+]=O)=CC=CC=1

C1[CH0+]=CC=CC=1

C(#[OH0+])C

respectively

Explanation:

The IR peak at 1687 cm⁻¹ is indicative of an α unsaturated carbonyl carbon. While the 1H NMR singlet is of the methyl group next to carbonyl and the multiplet near 7.1 ppm is a characteristic peak of benzene. This data shows points towards structure I.

Mass spectrum peak at 120 m/z is of molecular ion peak. In the case of carbonyl-containing molecule, this peak is observable. The signal at 105 shows the loss of a methyl group next to the carbonyl. m/z value of 77 is the characteristic cationic peak of benzene, while the peak at 43 infers the formation of acylium ion (RCO+) due to α-cleavage. All this data agrees with the structure of acetophenone (Structure 1)

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4 years ago
Describe the two methods of active transport.
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7 0
3 years ago
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A given reaction has an activation energy of 24.52 kj/mol. at 25°c, the half-life is 4 minutes. at what temperature will the hal
igor_vitrenko [27]
According to half life equation:

T(1/2) = ㏑2 / K1

when the T(1/2) = 4 min * 60 = 240 sec

by substitution:

240 = 0.6931 / K1

K1 = 2.9 x 10^-3

when the second T(1/2) = 20 sec, so to get K2:

T(1/2) = 0.6931 / K2

by substitution:

20 = 0.6931 / K2

∴K2 = 3.4 x 10^-2

so, we can get T2 by using this formula:

㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)

by substitution:

㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)

∴ T2 = 396.7 K

         = 396.7 - 273 = 123.7 °C 



4 0
4 years ago
The electronegativity is 2.1 for h and 1.9 for pb. based on these electronegativities pbh4 would be expected to
Sedbober [7]
PbH4 will be formed as a result of a polar covalent bond between the H and the Pb.

Since H is more electronegative than the Pb, it is, thus, expected that the H would be able to pull the electron charge towards itself. This will result in the H being negative.

Based on this:
PbH4 would be expected to <span>have polar covalent bonds with a partial negative charges on the H atoms. </span>
8 0
3 years ago
I really need help please someone help me?!.<br><br> Those are all the questions.
natima [27]

Answer:

question two is most likely you can describe the shape as a twisted ladder, thats what I learned in school.

Explanation:

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4 0
3 years ago
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