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KengaRu [80]
3 years ago
8

02 (s) + Pb(s) — PbO2(s) find the reduced and oxidized reactants

Chemistry
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

Oxygen is oxidizing gent and itself get reduced while lead is reducing agent and itself get oxidize.

Explanation:

Chemical  equation with oxidation state:

O⁰₂(s)  +  Pb⁰ (s)    →  Pb⁺⁴O₂⁻²(s)

Oxidizing agent:

Oxidizing agents, oxidize the other substance and itself get reduced. They can be identify by just looking the oxidation state. If oxidation state is decreased on the right side it means substance gain the electron and get reduced.

Reducing agent:

Reducing agents, reduce the other substance and itself get oxidize. They can be identify by just looking the oxidation state. If oxidation state is increased on the right side it means substance lose the electron and oxidation state increased.

In given chemical equation, oxygen and lead were in neutral form they react and form lead dioxide. In this product oxygen is oxidizing gent and itself get reduced and oxidation state change from 0 to -2 while lead is reducing agent, itself get oxidize and oxidation state change from o to +4.

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Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.

Explanation:

Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.

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A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.

B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.

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Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

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