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Arturiano [62]
3 years ago
7

After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

Percentage loss of the number of trees is 25\%.

Step-by-step explanation:

Given: After a storm, 135 trees out of 180 were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees =180

Number of trees left standing =135

Therefore, loss of trees=180-135=45

We now that \text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%

\implies \text {Loss\%}=\frac{45}{180}\times 100 \%

\implies \text {Loss\%}=\frac{450}{18} \%

\implies \text {Loss\%}=25 \%

Hence, the percentage loss of the number of trees is 25\%.

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Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

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b) In matrix form this is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)

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\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304

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\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)

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