Answer:
The answer to your question is V2 = 66.7 ml
Explanation:
Data
Volume 1 = V1 = 400 ml
Pressure 1 = P1 = 1 atm
Volume 2 = V2 = ?
Pressure 2 = P2 = 6 atm
Process
1.- To solve this problem use Boyle's law
P1V1 = P2V2
-solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (1)(400) / 6
-Simplification
V2 = 400 / 6
-Result
V2 = 66.7 ml
Pressure will decrease as volume increases, and vice-versa.
If the reaction is represented by:
PCl₃ + Cl₂ <-> PCl₅ (exothermic)
the mole fraction of chlorine in the equilibrium mixture will change according to the following:
Decrease the volume: decrease
Increase the temperature: increase
Increase the volume: increase
Decrease the temperature: decrease
Answer:
The order of elements by volume-fraction (which is approximately molecular mole-fraction) in the atmosphere is nitrogen (78.1%), oxygen (20.9%), argon (0.96%), followed by (in uncertain order) carbon and hydrogen because water vapor and carbon dioxide, which represent most of these two elements in the air, are variable.
I copied and pasted but I hope this information is helpful :)
Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
