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Lynna [10]
3 years ago
7

Given: 2NaCl the 2 is:

Chemistry
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

The answer to your question is the letter C.

Explanation:

Data

        2NaCl

When we write molecules we use numbers in two main different ways.

If the coefficients are at the beginning of the molecule, this number indicates the number of molecules presented.

If there are subscripts, this number indicates the quantity of that specific element.

So the correct answer is letter C because it describe the correct function of this coefficient.

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The plunger on a bicycle pump with a 400 mL volume cylinder is
Kobotan [32]

Answer:

The answer to your question is V2 = 66.7 ml

Explanation:

Data

Volume 1 = V1 = 400 ml

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = ?

Pressure 2 = P2 = 6 atm

Process

1.- To solve this problem use Boyle's law

                     P1V1 = P2V2

-solve for V2

                     V2 = P1V1 / P2

-Substitution

                      V2 = (1)(400) / 6

-Simplification

                      V2 = 400 / 6

-Result

                      V2 = 66.7 ml

4 0
3 years ago
a sample of gas is stored in a cylinder. If the temperature is kept constant and the piston moves up to increase the volume what
GrogVix [38]
Pressure will decrease as volume increases, and vice-versa.
8 0
4 years ago
Read 2 more answers
How will the following changes affect the mole fraction of chlorine gas, χcl2, in the equilibrium mixture.?
sammy [17]
If the reaction is represented by:
PCl₃ + Cl₂ <-> PCl₅ (exothermic)

the mole fraction of chlorine in the equilibrium mixture will change according to the following:
Decrease the volume: decrease
Increase the temperature: increase
Increase the volume: increase
Decrease the temperature: decrease
4 0
3 years ago
Which chemical element represents the most abundant “atoms of an element” found in air?
zalisa [80]

Answer:

The order of elements by volume-fraction (which is approximately molecular mole-fraction) in the atmosphere is nitrogen (78.1%), oxygen (20.9%), argon (0.96%), followed by (in uncertain order) carbon and hydrogen because water vapor and carbon dioxide, which represent most of these two elements in the air, are variable.

I copied and pasted but I hope this information is helpful :)

3 0
3 years ago
Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
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