A water molecule is composed of a large oxygen atom bonded to two small hydrogen atoms. Which of the following would make the be
st model of a water molecule?
A. A drawstring bag filled with blue, green, red, and yellow marbles
B. Four index cards printed with either an uppercase or lowercase letter
C. Two small, plastic balls attached to a larger plastic ball by toothpicks
D. A large, plastic bucket filled with dirt, dead leaves, and rocks
A. A drawstring bag filled with blue, green, red, and yellow marbles
B. Four index cards printed with either an uppercase or lowercase letter
C. Two small, plastic balls attached to a larger plastic ball by toothpicks
D. A large, plastic bucket filled with dirt, dead leaves, and rocks
2 answers:
Answer:
C. Two small, plastic balls attached to a larger plastic ball by toothpicks
Explanation:
One molecule of water has 1 oxygen atom and two atoms of hydrogen. Each hydrogen is attached to the oxygen by a simple bond, they share one pair of electron.
Because oxygen is larger than hydrogen, a manner to represent a single molecule is to have two small plastic balls (representing hydrogen) attached to a larger plastic ball (representing oxygen) by toothpicks (representing the bonds), such as the image below.
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Explanation:
(1). It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.
For example,
Hence, in a reaction equation you start with the reactants and end up with the products.
(2). The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.
Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.
Answer:
1. Yes
2.The solubility of X is 34.55g/L
Explanation:
Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm or 1 Litre of water.
From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved
= 0.019kg*1000 = 19g.
if 19g is required to saturate 550mL at 30°C,
then will saturate 1L
= 34.545g will saturate 1Litre
The solubility thus is 34.55g/L