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Gnoma [55]
3 years ago
12

1. The brilliant red colors seen in fireworks are due to the emission of light

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

what does c and m and n stand for?

Explanation:

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When the temperature of a rigid hollow sphere containing 685 L of helium gas is held at 621 K, the pressure of the gas is 1.89 x
Leno4ka [110]
You have to use the equation PV=nRT.
P=pressure (in this case 1.89x10^3 kPa which equals 18.35677 atm)
1V=volume (in this case 685L)
n=moles (in this case the unknown)
R=gas constant (0.08206 (L atm)/(mol K))
T=temperature (in this case 621 K)
with the given information you can rewrite the ideal gas law equation as n=PV/RT.
n=(18.35677atm x 685L)/(0.08206atmL/molK x 621K)
n=246.8 moles
8 0
3 years ago
How many cells in a unicellular organism function to get rid of waste?
Neporo4naja [7]
If its a unicellular orgnism, it has only one cell . no?
so i guess the answer has to be 1

3 0
3 years ago
The decomposition of nitryl chloride is described by the following chemical equation: 2NO2C1(g) → 2NO2 (g)-C12 (g) Suppose a two
Gnoma [55]

Answer:

Second reaction

NO2 + F -------> NO2F

Rate of reaction:

k1 [NO2] [F2]

Explanation:

NO2 + F2 -----> NO2F + F slow step1

NO2 + F -------> NO2F fast. Step 2

Since the first step is the slowest step, it is the rate determining step of the reaction

Hence:

rate = k1 [NO2] [F2]

6 0
3 years ago
If I contain 3 moles of gas in a container with a volume of 60 liters and at a
viktelen [127]

Answer:    n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT, you can find P

P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L

P = 1.642 atm = 1.6 atm (to 2 significant figures)

4 0
3 years ago
Read 2 more answers
Why should scientists control most possible variables in their experiments?
irina [24]
Scientists should control most possible variables in experiments to get the most valid and correct data. If many variables are included in experiments it is more difficult to interpret what is causing a different outcome.
8 0
3 years ago
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