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Nataly [62]
2 years ago
12

A boxed 10 kg computer monitor is dragged by friction 5.5 m up along the moving surface of a conveyor belt inclined at an angle

of 36.9° above the horizontal. If the monitor’s speed is a constant, how much work is done on the monitor by friction?
Chemistry
2 answers:
Ede4ka [16]2 years ago
5 0

Answer:

A lot, because it belt inclined at an angle of 36.9° above the horizontal.

I need points haha!

klemol [59]2 years ago
3 0

Answer:

324 J

Explanation:

58.84 * 5.5 J = 324 J

I got 58.84 by 10 * 9.8 (gravity) * sin(36.9)

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sergij07 [2.7K]

Answer:

4121 years

Explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2= half life of the carbon-14

No= count rate of the living tissue

N= count rate of the sample

t = age of the sample

0.693/5730 =2.303/t log (13.5/8.2)

1.21 * 10^-4 = 2.303/t * 0.2165

1.21 * 10^-4 = 0.4986/t

t = 0.4986/1.21 * 10^-4

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7 0
3 years ago
You have 100 g of Pb(NO3)2. How many moles is this?​
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Answer:

0.302 moles

Explanation:

Data given

Mass of Pb(NO₃)₂ = 100 g

Moles of Pb(NO₃)₂ = ?

Solution:

To find mole we have to know about molar mass of Pb(NO₃)₂  

So,

Molar mass of Pb(NO₃)₂  = 207 + 2[14 + 3(16)]

                                           = 207 + 2[14 + 48]

                                           = 207 + 124

Molar mass of Pb(NO₃)₂  = 331 g/mol

Formula used :

                no. of moles = mass in grams / molar mass

Put values in above formula

                   no. of moles = 100 g / 331 g/mol

                   no. of moles = 0.302 moles

no. of moles of  Pb(NO₃)₂ = 0.302 moles

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