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4 years ago

If a star of 50 solar masses were to supernova, it would most likely become a _____.

Chemistry

2 answers:

k0ka [10]4 years ago

8 0

Answer: e. black hole

Explanation:

A Massive star either ends up as neutron star or a black hole.

When fuel is used up, the star expands and becomes a Red super giant and goes supernova. Most of the material is thrown out which forms planetary nebula. The core collapses in seconds to form Neutron star or black hole. A star having mass more than 3 solar masses usually collapses to form black hole.

Thus, a 50 solar mass star would likely become a black hole after it goes supernova.

alexandr1967 [171]4 years ago

7 0

The answer is Black Hole.

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The elements in yellow are referred to as ___________.

Lemur [1.5K]

Answer:

Metalloids

Explanation:

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8 0

3 years ago

A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?

Ira Lisetskai [31]

Answer:

$\lambda=540.16\ nm$

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = $2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J$

Considering

$Energy=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Thus,

$3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}$

$3.68\times \:10^{26}\lambda=1.9878\times 10^{20}$

$\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=540.16\ nm$

3 0

4 years ago

Which net ionic equation would match this description of a chemical reaction: When a

krok68 [10]

Answer:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

Explanation:

$Mg(NO_{3})_{2}$ , $Na_{3}PO_{4}$ are strong electrolytes. Hence they are fully ionized in aqueous solution.

$Mg_{3}(PO_{4})_{2}$ is a sparingly soluble salt. Hence it remains undissociated in aqueous solution.

So, total ionic equation:

$3Mg^{2+}(aq.)+6NO_{3}^{-}(aq.)+6Na^{+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)+6Na^{+}(aq.)+6NO_{3}^{-}(aq.)$

Net ionic equation is written by omitting spectator ions from total ionic equation.

Here, $Na^{+}$ and $NO_{3}^{-}$ ions are spectator ions as they remain present on both side of total ionic equation.

So, net ionic equation:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

So, option (d) is correct.

6 0

3 years ago

What is the concentration of OH− in a solution with a pOH value of 6.09

djyliett [7]

Answer:

I'm not sure

Explanation:

I'm just not sure

5 0

2 years ago

Barium (Ba) is an alkaline earth metal.<br><br>t or f

tatiyna

Barium is a chemical element with symbol Ba and atomic number 56. It is the fifth element in group 2 and is a soft, silvery alkaline earth metal. Because of its high chemical reactivity, barium is never found in nature as a free element. Thanks and I hope it helped.

8 0

4 years ago