Such ions are said to be isoelectronic
Flourine.
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They are also called the noble gases or inert gases. They
are virtually unreactive towards other elements or compounds. They are found in
trace amounts in the atmosphere. Their elemental form at room temperature is
colorless, odorless and monatomic gases. They also have full octet of eight
valence electrons in their highest orbitals so they have a very little tendency
to gain or lose electrons to form ions or share electrons with other elements
in covalent bonds.
Answer:
Astatine is a halogen with several isotopes that all have short half-lives.
Which of the following combinations of mass number and neutrons are possible as isotopes of astatine? Choose one or more:
i) A = 211, n = 127
ii) A = 210, n = 125
iii) A = 220, n = 134
iv) A = 207, n = 122
v) A = 209, n = 124
Explanation:
The mass number is the sum of the number of protons and the number of neutrons in an atom.
Atomic number of At(astatine ) =85
That means it has --- 85protons.
Its mass number A=210
Hence, the number of neutrons in At are:

Second option:
ii) A=210 , n=125 is the answer.
<h3>
Answer:</h3>
1.52 × 10⁻¹⁶ nm
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Explanation:</h3>
We are given,
Energy = 3.36 × 10⁻¹⁷ Joules
We are required to find the wavelength of light
We are going to use,
The formula, E = hλ/c
Where E is the energy, λ is the wavelength, h is the plank's constant and c is the speed of light.
h = 6.626 × 10^-34 J-s
c = 2.998 × 10^8 m/s
Working
From the formula;

= (3.36 × 10⁻¹⁷ J)(2.998 × 10^8 m/s) ÷ 6.626 × 10^-34 J-s
= 1.52 × 10⁻²⁵ meters
Therefore, the wavelength in m is 1.52 × 10⁻²⁵ m
Conversion
We need to convert m to nm
Conversion factor is 10⁹
Therefore;
1.52 × 10⁻²⁵ m to nm
will be; 1.52 × 10⁻²⁵ m × 10⁹
= 1.52 × 10⁻¹⁶ nm
Thus, the wavelength in nm is 1.52 × 10⁻¹⁶ nm