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tigry1 [53]
1 year ago
5

How much energy would be released as an electron moved from the n=4 to the n=3 energy level?

Chemistry
1 answer:
Thepotemich [5.8K]1 year ago
8 0

The energy released when electron move from n=4 to n=3 is 0.66 eV

We know that in an atom energy of nth state is

                                     E_n =  -13.6/n^{2}  eV

where n is the energy level

Therefore,

                   E_4 = -13.6/4^{2} \\E_3  = -13.6/3^{2}

Thus, E_4  =   -0.85eV

         E_3  =  -1.51eV

Therefore, total mount of energy released in moving electron from n=4 to n=3 is given by -

                                       E_4 -E_3

                                   =  -0.85 - ( -1.51)

                                   = 0.66eV

To know more about energy released in electron transition

brainly.com/question/8384785

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At a certain temperature 3.24 moles of co2 gas at 2.15atm takes up a volume of 35.28 what is the temperature in celsius
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The temperature is 12.35 C.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

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In this case:

  • P= 2.15 atm
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2.15 atm* 35.28 L= 3.24 moles* 0.082\frac{atm*L}{mol*K} * T

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<u><em>The temperature is 12.35 C.</em></u>

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