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tigry1 [53]
2 years ago
5

How much energy would be released as an electron moved from the n=4 to the n=3 energy level?

Chemistry
1 answer:
Thepotemich [5.8K]2 years ago
8 0

The energy released when electron move from n=4 to n=3 is 0.66 eV

We know that in an atom energy of nth state is

                                     E_n =  -13.6/n^{2}  eV

where n is the energy level

Therefore,

                   E_4 = -13.6/4^{2} \\E_3  = -13.6/3^{2}

Thus, E_4  =   -0.85eV

         E_3  =  -1.51eV

Therefore, total mount of energy released in moving electron from n=4 to n=3 is given by -

                                       E_4 -E_3

                                   =  -0.85 - ( -1.51)

                                   = 0.66eV

To know more about energy released in electron transition

brainly.com/question/8384785

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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
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Determine the number of protons, neutrons, and electrons for a neutral potassium-41 isotope.
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6 0
3 years ago
g What is the molarity of hydrochloric acid if 40.95 mL of HCl is required to neutralize 0.550 g of sodium oxalate, Na2C2O4
kykrilka [37]

Answer:

0.0002 M

Explanation:

<em>The molarity of the HCl required would be 0.0002 M.</em>

First, let us consider the balanced equation of the reaction:

Na_2C_2O_4 + 2HCl = 2NaCl + H_2 + 2CO_2

<em>Stoichiometrically, 1 mole of </em>Na_2C_2O_4<em> reacts with 2 moles of </em>HCl<em> for a complete neutralization reaction.</em>

Recall that: mole = \frac{mass}{molar mass}

Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole

<em>If 1 mole </em>Na_2C_2O_4<em> requires 2 moles HCl, then 0.0041 mole will require</em>:

    0.0041 x 2 = 0.0082 mole HCl

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Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M

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3 years ago
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