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bearhunter [10]
3 years ago
12

Mike is conducting an experiment inside an Erlenmeyer flask, and he has the top of the flask sealed with a balloon to capture an

y gaseous products that may be produced. Is Mike's experimental setup an example of a closed, open, or isolated system
Chemistry
1 answer:
zhenek [66]3 years ago
5 0

Answer:

Closed system

Explanation:

In order to do this, let's remember the concepts of an open, closed and isolated system.

Open system: Any matter and heat can enter or leave the system.

Closed system: any matter cannot enter or leave the system, however heat can enter or leave the system.

Isolated system: neither matter nor heat can enter or leave the system.

Now, an open system cannot be, cause the flask is sealed at the top with a balloon, so matter cannot escape the system.

Now, in general terms, an erlenmeyer flask is not insulated to prevent that any heat or energy can be transfered, hence, the system, even with the balloon to prevent any escape of the gaseous product, it can still transfer heat or energy to the medium. This can be verified by touching the balloon or flask, therefore, is a closed system.

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olga2289 [7]

Answer:

exothermic reaction

Explanation:  

I think this because this is an example of an exothermic reaction is the chemical reaction between sodium and chlorine, which results in the formation of sodium chloride (also known as common salt)

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Answer:

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Explanation:

Arteries carry oxygenated blood from the heart, while veins carry oxygen-depleted blood back to the heart. ... The pulmonary veins transport oxygenated blood back to the heart from the lungs, while the pulmonary arteries move deoxygenated blood from the heart to the lungs.)

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2 years ago
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Oduvanchick [21]

Answer:

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3 years ago
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pishuonlain [190]
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3 years ago
The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:
Elina [12.6K]

\huge \underbrace \mathfrak \red{Answer}

28%

Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

\sf \large {mass \: percentage =  \frac{mass \: of \: solute}{mass \: of \: solvent}  \times 100} \\  \\  \sf  mass \: percentage =  \frac{3.73}{134.73}  \times 100 \\  \\  \sf mass \: percentage =  0.028 \times 100 \\  \\  \sf mass \: percentage = 28\%

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2 years ago
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