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KATRIN_1 [288]
3 years ago
7

Octane C8H18 is an ingredient in gasoline. How many carbon atoms are in 20 kg of octane? help please

Chemistry
2 answers:
abruzzese [7]3 years ago
4 0

Answer:

Explanation:

Octane is C8H18, carbon is C. Therefore, for every mol of C8H18 there will be 8 mols of carbon.

Convert 20 kg of octane to mols octane using molar mass of octane.

Molar Mass octane = (8*12.011)+(18*1.008)=114.23 g/mol, where 8 and 18 are the atoms in the molecule and 12.011 and 1.008 are the respective molar masses of carbon and hydrogen.

20kg C8H18 *1000g/kg * mol C8H18/114.23g C8H18 = 175.1 mols octane.

Now convert that number of mols to mols carbon:

175.1 mol C8H18 * (8 mol C/mol C8H18)=1400.8 mol C.

Now remember that a mol of any given atom=6.022*10^23 atoms.

So 1400.8 mol C=1400.8*(6.022*10^23) atoms C, which is equal to your final answer, 8.4*10^26 atoms. (round to 2 significant digits since the initial number given, 20, has 2 significant digits.)

The main thing you want to look for here is your conversion factors. Once you have those down it is simple algebra from there, so be sure to practice those!

eduard3 years ago
3 0

Answer:

Octane is a hydrocarbon and an alkane with the chemical formula C 8 H 18, and the condensed structural formula CH 3 (CH 2) 6 CH 3.Octane has many structural isomers that differ by the amount and location of branching in the carbon chain. One of these isomers, 2,2,4-trimethylpentane (commonly called iso-octane) is used as one of the standard values in the octane rating scale.

Chemical formula: C₈H₁₈

Molar mass: 114.232 g·mol−1

Melting point: −57.1 to −56.6 °C; −70.9 to −69.8 °F; 216.0 to 216.6 K

Solubility in water: 0.007 mg dm−3 (at 20 °C)

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What is the concentration of an naoh solution that requires 15.0 ml of a 0.750 m h2so4 solution to neutralize 17.5 ml of naoh?
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So the first thing we must do is write a balanced equation for the reaction and we know the equation is balnced when all the species on the RHS is equal to the species on the LHS
                      2NaOH  +  H₂SO₄   →  Na₂SO₄<span>  +  2H₂O
</span>
So now it's time to identify what reactant you know the most for from the question (volume & conc. of H₂SO₄) and use that info to find the unknown (conc. of NaOH)

If 1000 ml  of H₂SO₄ contain 0.750 mol   [0.750 M is the amount of moles in 
                                                                       1 L (1000 ml)]
then let 15 ml of H₂SO₄ contain x mol     [15 ml is the amount of the acid that                                                                                  took part in the reaction]
    
⇒  x  =  \frac{15ml    *    0.750 mol}{1000 ml}
       
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Mole ratio of NaOH  to  H₂SO₄  can be obtained from the balanced equation
                 0 2NaOH  +  1H₂SO₄   →  Na₂SO₄  +  2H₂O

    mole ratio of   NaOH  to  H₂SO₄  is 2 : 1

∴ if mole of of H₂SO₄   =  0.01125 mol
   then moles of NaOH = (0.01125 mol) × 2
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If 17.5 ml of NaOH contain 0.0225 mol      [this was given in the question]
then let 1000 ml of NaOH contain  x

⇒ x  =  \frac{1000ml   * 0.0225 mol}{17.5 ml}
       
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∴ concentration of NaOH is 1.286 mol/L 

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Answer:

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