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telo118 [61]
3 years ago
13

Julio's goal is to type an average of 50 words per minute on his five typing exams. His scores on the first four exams were 46,4

4,57 and 47 words per minute. How many words per minute will he need on his fifth exam to reach his goal?
Options: 56,58,50,51

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
Answer is 56 because on his 3rd exam he got 57 word per minute, since he got 57 he can take out 7 of those words and he would still have 50. Remember the extra 7 words we have. Then you would calculate how many more words he needs to get to fifty on his other exams which are 4,6,and 3. Add these 3 and you get 13. Remember we still have that extra 7. We pick 56 with the extra 7 it would be 63. You can take out 13 words to fill in the other exams and u would still be left with 50.
Therefor your answer is 56.
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Algebra 2 help? Will give brainliest
Sergio [31]

Step-by-step explanation:

if |A|≥B then

A≥B or A≤-B

4x-10≥14 or 4x≤-14

solve 4x-10≥14

add 20 on both sides

4x≥10+14

4x≥24

divide by 4 on both ends

x≥24/4

x≥6

now solve

4x-10≤-14

add 10 on both sides

4x≤-14+10

4x≤-4

divide both sides by 4

x≤-1

(-∞,-1] U [6,∞)

6 0
3 years ago
What is the value of x?
denis-greek [22]

Answer:

12

Step-by-step explanation:

4 0
3 years ago
A music festival charges $54.95 per ticket sold on the day of the event. A ticket purchases before the festival costs only $39.9
Wewaii [24]
B=number of ticets sold before
a=number of tickets sold after

cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a

total cost=925000
39.95b+54.95a=925000

total number tickets=20000
b+a=20000

we have

39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000

15a=126000
divide bot sides by 15
a=8400

sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600




11,600 tickets sold before
8400 tickets sold after
7 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 419 gram setting. It is
Dahasolnce [82]

Answer:

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given the mean of the Population(μ)  = 419 grams

The sample size 'n' =19

Given mean of the sample x⁻ = 412

Given variance of the sample S² = 784

                                                 S = √784 = 28

<u><em>Step(ii)</em></u>:-

<u><em>Null hypothesis: H₀</em></u>: There is no sufficient evidence to support the claim that the bags are underfilled.

<u><em>Alternative hypothesis: H₁:</em></u>

There is sufficient evidence to support the claim that the bags are underfilled.

Test statistic

                     t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                    t = \frac{412 -419}{\frac{28}{\sqrt{19} } }

                   t = -1.09

                 |t| = |-1.09|

<em>Degrees of freedom   ν = n-1 = 19-1 =18</em>

<em>t₀.₀₂₅ =  3.19</em>

<u><em>Final answer:</em></u><em>-</em>

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

                   

8 0
3 years ago
Graph the line y+3=-1/4(x-3)
insens350 [35]

Answer:

Make a table with values of x and y using the equation y + 3 = -1/4(x - 3) :

x         y

0     -2.25

3        -3

5      -3.5

-1       -2

-9       0

Now, graph these and draw a line through the points:

4 0
2 years ago
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