A music festival charges $54.95 per ticket sold on the day of the event. A ticket purchases before the festival costs only $39.9
5. They were 20,000 tickets sold for a total of 925,000. How many tickets did they sell at the music festival? How many tickets do they sell before the music festival?
B=number of ticets sold before a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket beforecost=39.95b aftercost=54.95a
total cost=925000 39.95b+54.95a=925000
total number tickets=20000 b+a=20000
we have
39.95b+54.95a=925000 b+a=20000 multiply second equation by -39.95 and add to first equatin 39.95b+54.95a=925000 <u>-39.95b-39.95a=-799000 +</u> 0b+15a=126000
15a=126000 divide bot sides by 15 a=8400
sub back b+a=20000 b+8400=20000 minus 8400 both sides b=11600
11,600 tickets sold before 8400 tickets sold after
Let's assume that a,b&c are in one straight line, so cannot form a triangle with each other. Now, total possible Triangle that can be formed choosing any 3 points without any colinear constraint is 8C3 = 56
