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svet-max [94.6K]
4 years ago
5

Which best describes how energy changes form in a car's engine?

Physics
2 answers:
andrezito [222]4 years ago
6 0

Answer:

Multiple transformations occur because the chemical energy of the fuel is changed to several forms of energy

Explanation:

In a car engine, multiple energy transformation takes place. The chemical energy storef in fuel is transformed into mechanical energy which helps move the wheels of the vehicle.

The mechanical energy can also be transformed into electrical energy through a sort of dynamo system in vehicles. Stereo players use the electrical energy to produce sound.

We see that multiple energy conversions are common in a motor car.

andreev551 [17]4 years ago
3 0

Answer:

C. Multiple transformations occur because the chemical energy of the fuel is changed to several forms of energy.

Explanation:

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We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
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3 years ago
29) A load is placed on a 1.5-kg cart. A force of
Goryan [66]
Answer: 0.5 kg
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3 years ago
In addition to stand-alone discussion boards, all of these sites include discussion boards as part of their features except: ​
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8 0
3 years ago
Convert 9.065 m to<br> cm<br> 90.65<br> 906.5<br> 9065<br> 0.0965<br> SUBMIT ANSWER
DedPeter [7]

Answer:

906.5 cm

Explanation:

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8 0
3 years ago
Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity
MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

v_{12} = v_1 - v_2

here

speed of first plane is 700 mi/h at 31.3 degree

v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j

v_1 = 598.12\hat i + 363.7\hat j

speed of second plane is 570 mi/h at 134 degree

v_2 = 570 cos134 \hat i + 570 sin134 \hat j

v_2 = -396\hat i + 410\hat j

now the relative velocity is given as

v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j

v_{12} =994.12\hat i -46.3 \hat j

now the distance between them is given as

d = v* t

d = (994.12 \hat i - 46.3 \hat j)* 3

d = 2982.36\hat i - 138.9\hat j

so the magnitude of the distance is given as

d = \sqrt{2982.36^2 + 138.9^2}

d = 2985.6 miles

so the distance between them is 2985.6 miles

5 0
3 years ago
Read 2 more answers
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