Answer:
Part a)

Part b)

Explanation:
Part a)
As we know that orbital velocity at certain height from the surface of Earth is given as

here we know that



now we have


Part b)
When a loose rivet is moving in same orbit but at 90 degree with the previous orbit path then in that case the relative speed of the rivet with respect to the satellite is given as

<span>The wires are suspended diagonally, meaning the tension in each is directed diagonally as well (along the wire). We can, however, talk about the horizontal and vertical components of the tension force. The horizontal tension force in each wire is Tcosθ, while the vertical tension force is Tsinθ.
The horizontal tension forces balance one another, because the wires are pulling in opposite directions. This means Tcosθ=Tcosθ, which is obvious but not very helpful. If you look at the vertical tension forces on the other hand, you can see that they must balance the weight of the body for the system to be in equilibrium. In other words:
Tsinθ+Tsinθ=mg
You're given enough information in the question to solve for T using this equation!</span>
Answer:

Explanation:
From the Question we are told that:
Mass 
Coefficient of kinetic friction 
Generally the equation for Frictional force is mathematically given by



Generally the Newton's equation for Acceleration due to Friction force is mathematically given by



Therefore



Answer:
The answer to your question is T2 = 580.5 °K
Explanation:
Data
Temperature 1 = T1 = 273°K
Pressure 1 = P1 = 388 kPa
Pressure 2 = P2 = 825 kPa
Temperature 2 = ?
Process
1.- Use the Gay-Lussac law
P1/T1 = P2/T2
-Solve for T2
T2 = P2T1/P1
-Substitution
T2 = (825)(273) / 388
-Simplification
T2 = 225225 / 388
-Result
T2 = 580.5 °K