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STALIN [3.7K]
3 years ago
14

Are normal salts acidic, basic or neutral salt?

Chemistry
1 answer:
RSB [31]3 years ago
8 0
Neutral salt is the answer



Hope this helps!
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Chemical formula for tin iv carbide
aniked [119]

Answer:

Explanation:

Sn(WC)2

if it is tungsten carbide this should be correct but there are many versions of carbide

Sn(MC2)2

could also be possible

the 2 next to MC should be a subscript

3 0
3 years ago
11
Bess [88]

Answer:

Explanation:

<u>Manganese (VII) ion (an anion) has the formula MnO₄⁻</u>. A polyatomic ion is an ion that is made up of more than one atom. For example, MnO₄⁻ and NH₄⁺. Since the ion provided in the question is an anion, the polyatomic ion that would react with it will have to be a cation (positively charged).

<u>The polyatomic cation that will react with MnO₄⁻ to form a neutral compound is NH₄⁺ (ammonium ion) to form NH₄MnO₄ (Ammonium permanganate).</u>

6 0
2 years ago
The function of this organelle is to create energy (ATP) through the process of cellular respiration.
dedylja [7]

Answer:

C

Explanation:

I hope this is correct and have a great day

3 0
3 years ago
Read 2 more answers
Can anyone help me please?
Nady [450]

10. Is A

11. Is D

12. Is D

13. Is B

5 0
3 years ago
Find the oxidizing agent and the reducing agent.
Vladimir [108]
Oxidizing agent is that which is reduced and the reducing agent is that which is oxidized. Reduced is when the charged is decreased and oxidized when the charge is increased.

(1)  2Na + 2H2O(l) --> 2NaOH(aq) + H2(g)
The charge of Na in the reactant is 0 and the charge of Na in the NaOH is +1. Na is oxidized. Hence, it is the reducing agent. 

The charge of H in H2O is +1 while that in H2 is 0. H is reduced. Hence, it is the oxidizing agent.

(2)  C(s) + O2(g) --> CO2(g)

The charge of C in the reactant side is 0 and that its charge in CO2 is +4. C is oxidized. Hence, it is the reducing agent. 

The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.

(3)  2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺

The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.

The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent. 
8 0
3 years ago
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