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zepelin [54]
3 years ago
5

In a neutral atom, the number of protons _______ the number of electrons.

Chemistry
2 answers:
sergejj [24]3 years ago
8 0

Answer:

equal the number of electrons.

Explanation:

Blababa [14]3 years ago
5 0

Answer:

Is equal to the number of electrons

Explanation:

B/c the net charge between them will be zero.

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What is the formula of titanium(IV) bromide?
IgorLugansk [536]
The answer is TiBr4 which is the formula
4 0
3 years ago
A student is given a sample of an unknown liquid to test in the laboratory. The student thinks that the liquid is water. Which o
erastova [34]

Answer:

This question is incomplete, the options are:

(A) color of the liquid

(B) mass of the liquid

(C) the volume of the liquid

(D) the boiling point of the liquid

The answer is D

Explanation:

Substances at different states usually possess certain properties that distinguishes them. For example, in this case involving a student who was given a sample of an unknown liquid to test in the laboratory, he thinks that the unknown liquid is water. Specific properties of the unknown liquid can be used to identify whether it is water or not.

One property that can be used to ascertain whether or not it is water is the boiling point of the liquid. This is because specific liquids have specific boiling point. So if the unknown liquid has a boiling point of 100°C, then it can be ascertained to be water.

6 0
3 years ago
What is the mass of 23450 L of hydrogen gas at STP
WINSTONCH [101]
Remember that in this case pressure is equal to 1.00 atm and temperature is equal to 273.15K. So,
P
V
=
n
R
T
→
n
=
P
V
R
T
=
1.00
a
t
m
⋅
7.0
L
0.082
a
t
m
⋅
L
m
o
l
⋅
K
⋅
273.15
K
=
0.31
Since we know hydrogen's molar mass (
2.0
g
m
o
l
), we can determine the mass
m
H
2
=
n
⋅
m
o
l
a
r
.
m
a
s
s
=
0.31
m
o
l
e
s
⋅
2.0
g
m
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g
If indeed you are dealing with STP, remember that, under these conditions, 1 mole of any ideal gas occupies
22.4
L
. So,
n
=
V
V
m
o
l
a
r
=
7.0
L
22.4
L
=
0.31
moles
And, once again,
m
=
0.31
⋅
2.0
=
0.6
4 0
3 years ago
When looking at the equilibrium between calcium sulfate and its aqueous ions, what could be added to solution to promote precipi
Lorico [155]

The common ion effect is the decreased solubility of the ionic precipitate in the solution. To promote the precipitation of the calcium sulfate, magnesium sulfate must be added.

<h3>What is the common ion effect?</h3>

It is a phenomenon that is due to the addition of the common ion already present in the solution that affects the equilibrium and is used to decrease the solubility of the solute present in the solution to increase the precipitation rate.

Magnesium sulfate will be added to the solution as it already contains the sulfate ion in the form of calcium sulfate. This will increase the precipitation of the compound as the common ion added will decrease the solubility.

Therefore, magnesium sulfate will be added to promote precipitation.

Learn more about common ion effect here:

brainly.com/question/17278748

#SPJ1

5 0
1 year ago
If 30.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 40.0 mL of 0.175 M HCl, what is the concentration of the C
Over [174]

Answer:

Concentration of Ca(OH)₂:

0.117 M.

Explanation:

How many moles of HCl is consumed?

Note the unit of concentration: moles per liter solution.

c(\text{HCl}) = 0.175\;\text{M} = 0.175\;\text{mol}\cdot\textbf{L}^{-1}.

Convert milliliters to liters.

V(\text{HCl})=40.0\;\text{mL} = 0.0400\;\text{L}.

n(\text{HCl}) = c(\text{HCl})\cdot V(\text{HCl})= 0.175\;\text{mol}\cdot\text{L}^{-1} \times 0.0400\;\text{L}= 7.00\times 10^{-3}\;\text{mol}.

How many moles of NaOH in the solution?

Refer to the equation. The coefficient in front of Ca(OH)₂ is 1. The coefficient in front of HCl is 2. In other words, it takes two moles of HCl to neutralize one mole of Ca(OH)₂. That 7.00\times 10^{-3}\;\text{mol} of HCl will neutralize only half that much Ca(OH)₂.

\displaystyle n(\text{Ca}(\text{OH})_2)=\frac{1}{2}\;n(\text{HCl}) = 3.50\times 10^{-3}\;\text{mol}.

What's the concentration of the Ca(OH)₂ solution?

Concentration is the number of moles of solute per unit volume.

\displaystyle c(\text{Ca}(\text{OH})_2) = \frac{n(\text{Ca}(\text{OH})_2)}{V(\text{Ca}(\text{OH})_2)} = \frac{3.50\times 10^{-3}\;\text{mol}}{0.0300\;\text{L}}=0.117\;\text{mol}\cdot\text{L}^{-1}.

3 0
3 years ago
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