Answer:
4.07L of a 0.110M NaF are needed
Explanation:
Based on the reaction:
SrCl₂(aq)+2NaF(aq)⟶SrF₂(s)+2NaCl(aq)
<em>1 mole of strontium chloride react with 2 moles of NaF</em>
<em />
361mL of 0.620M SrCl₂ solution has:
0.361L ₓ (0.620mol / L) = 0.22382 moles SrCl₂.
Moles of NaF for a complete reaction must be:
0.22382 moles SrCl₂ ₓ (2 mol NaF / 1 mol SrCl₂) = <em>0.44764 moles of NaF</em>
If you have a solution of 0.110M NaF, the moles of NaF needed are:
0.44764 moles of NaF ₓ (1L / 0.110mol NaF) = <em>4.07L of a 0.110M NaF are needed</em>
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D.The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation
</h3>
Conservation of mass states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
So it can be concluded
- mass of the reactants = mass of the products
- mass cannot be created or destroyed
- The number of atoms involved in a reaction remains the same⇒ number of moles also the same
- chemical equation in balanced form
So the number of atoms in reactants and products remains the same
Because one of the reactants in a reaction is Na₂O, so <em>The products will have at least 2 Na atoms and 1 O atom.</em>
Answer:
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