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3 years ago

15

Define the following terms . 1. Element 2. Mixture 3. Compound

1 answer:

icang [17]3 years ago

4 0

1- Fundamental materials of any matter
2- a material made up of two or more different substances
3- something composed of two or more separate elements

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Here is the electron configuration for Magnesium. How many total electrons are in the 2nd energy level?

balandron [24]

Answer:

8 electrons

Explanation:

Magnesium is present on group 2.

It has 2 valence electrons.

Electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

1st energy level contain 2 electrons.(1s²)

2nd energy level contain 8 electrons. (2s² 2p⁶)

3rd energy level contain 2 electrons. (3s²)

3rs energy level of magnesium is called valence shell. It contain two valance electrons. Magnesium can easily donate its two valance electrons and get stable electronic configuration.

It react with halogens and form salt. For example,

Mg + Cl₂ → MgCl₂

7 0

3 years ago

Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

3 0

3 years ago

Magnesium and bromine react to produce magnesium bromide. What is the balanced chemical equation for this reaction?

tia_tia [17]

Answer:

MgBr2

Explanation:

On the periodic table, Magnesium has 2+ charge and Bromine has -1 charge.

You cross charges and get MgBr2

6 0

3 years ago

Under certain conditions, the equilibrium constant of the reaction below is Kc=1.7×10−3. If the reaction begins with a concentra

svetoff [14.1K]

Answer:

[Cl2] equilibrium = 0.0089 M

Explanation:

<u>Given:</u>

[SbCl5] = 0 M

[SbCl3] = [Cl2] = 0.0546 M

Kc = 1.7*10^-3

<u>To determine:</u>

The equilibrium concentration of Cl2

<u>Calculation:</u>

Set-up an ICE table for the given reaction:

$SbCl5(g)\rightleftharpoons SbCl3(g)+Cl2(g)$

I 0 0.0546 0.0546

C +x -x -x

E x (0.0546-x) (0.0546-x)

$Kc = \frac{[SbCl3][Cl2]}{[SbCl5]}\\\\1.7*10^{-3} =\frac{(0.0546-x)^{2} }{x} \\\\x = 0.0457 M$

The equilibrium concentration of Cl2 is:

= 0.0546-x = 0.0546-0.0457 = 0.0089 M

5 0

3 years ago

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Frost is dew that forms when the air temperature is______

SOVA2 [1]

The answer is B. Below freezing

6 0

3 years ago

Read 2 more answers