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3 years ago

Consider two particles of equal masses attached to each other by a light straight spring write the lagrangian center of mass

1 answer:

5 0

<span>The lagrangian center of mass between two particles of equal mass can be calculated using the following equation: L=12MV2â’Uext.+Nâ‘i=112mi~v2iâ’Uint. M=â‘mi is the total mass, V is the speed of the center of mass, Uext.=â‘Uext.,i, and ~vi is the speed of the ith particle relative to the center of mass.</span>

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A car's acceleration is 3m/s2. If the car started at rest and it only took 10s for the car to reach this acceleration, what is t

Grace [21]

Answer:

30m/s

Explanation:

From law of motion equation

Vf= Vi + at

Where Vf= final velocity

Vi= initial velocity=0(the car started at rest)

a= acceleration= 3m/s2

t= time= 10s

Then substitute into the equation to get the final velocity.

Vf= 0+(10×3)

Vf= 30m/s

Hence, the car's final velocity is 30m/s

5 0

3 years ago

Ryan wants to transform electrical energy into light energy. He decides to build a complete circuit that will operate a light bu

Fofino [41]

C. is the answer. You can't use plastic because it does not conduct electricity and string does not conduct electricity either so the circuit will end before it get to the bulb.

5 0

4 years ago

Read 2 more answers

1. An object is moving in a straight line at constant speed. Which of the following is true?

liberstina [14]

c. II and III only (the object has 0 acceleration and the object has constant velocity.)

Why?

Let's discard each of the given options to find the correct one(s).

<h3>- There are no forces acting on the object:</h3>

False, if an object has a constant speed, it does not mean that there are no forces acting on it, in fact, there will be always acting forces, like frictional force, gravity force, air resistance, and others.

<h3>- The object has a 0 acceleration:</h3>

True, in an object is moving at constant speed, it means that there is no acceleration, the speed will be the same all the time during motion.

<h3>- The object has constant velocity:</h3>

True, <u>if an object is moving in a straight line at constant speed</u> the velocity will be also constant. The velocity of an object is referring to its speed and its direction, if the object is moving in a straight line, the direction will be the same, so, if the speed is constant, the velocity will be also constant.

Have a nice day!

3 0

3 years ago

A device consisting of four heavy balls connected by low-mass rods is free to rotate about an axle. It is initially not spinning

zubka84 [21]

The angular speed of the device is 1.03 rad/s.

<h3>What is the conservation of angular momentum?</h3>

A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.

Using the conservation of angular momentum

$L_{i}=L_{f}$

Here, = the system's angular momentum before the collision

$L_{i}$ = 0 + mv

= (0.005)(450)(0.752)

= 1.692 kgm²/s

The moment of inertia of the system is given by

I = 2(M₁R₁² + M₂R₂²)+ mR₁²

= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²

= 1.6292 kgm²

Here, = Iω

So,

1.692 = 1.6292(ω)

ω = 1.03 rad/s

To know more about the conservation of angular momentum, visit:

brainly.com/question/1597483

#SPJ1

4 0

1 year ago

Read 2 more answers

An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A

melamori03 [73]

Answer:

t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

$\omega = \frac{\theta}{t}$

<em>Where θ: is the angular displacement = π (since it moves halfway through a complete circle)</em>

We have:

$t = \frac{\theta}{\omega} = \frac{\theta}{v/r}$

<u>Where</u>:

<em>v: is the tangential speed </em>

<em>r: is the radius</em>

The radius can be found equaling the magnetic force with the centripetal force:

$qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}$

Where:

m: is the mass of the alpha particle = 6.64x10⁻²⁷ kg

q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C

B: is the magnetic field = 0.155 T

Hence, the time is:

$t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s$

Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.

I hope it helps you!

4 0

3 years ago