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Hunter-Best [27]
3 years ago
7

Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel across a 30 V potential difference t

o a light bulb. a. Calculate the current delivered through the light bulb in the two cases. b. Draw the circuit connection that will achieve the brightest light bulb​
Physics
1 answer:
Goshia [24]3 years ago
5 0

Answer:

<h2><u>plz mark as a pure substance abuse and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for </u></h2>
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The object is also positively charged because same or alike charges repel

Explanation:

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what are the answer choices?

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Speed is the rate of change in
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Speed is the rate of change <span>of distance.</span>
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3 years ago
Read 2 more answers
A car is driving 25.5 m/s when it hits
IceJOKER [234]

Answer:

it takes the car 4.362 seconds to cover the distance of 88.4 m.

Explanation:

The distance the car covers is given by the function

x(t) = vt-\dfrac{1}{2}at^2,

where v = 25.5m/s , and a = 2.40m/s, putting  these in we get:

x(t) = 25.5t-\dfrac{1}{2}(2.4)t^2\\\\x(t) = 25.5t-1.2t^2

Now, when the car has moved to 88.4m, x(t) = 88.4 , or

x(t) = 25.5t-1.2t^2 = 88.4

which is a quadratic equation with solutions

t = 4.362s,\\t = 16.887s

We take the first solution t = 4.362s, <em>since at that time the car is still moving right and decelerating</em>. The second solution t =16.887 describes the situation where the car has stopped decelerating and is now moving leftwards because the decelerating is leftwards, <em>which is utterly wrong because we know that cars do not start moving backwards after the brakes have stopped them! </em>

Thus, it takes the car 4.362 seconds to cover the distance of 88.4 m.

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3 years ago
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