Answer:
The right response will be "450 volts".
Explanation:
The given values are:
R1 = 4.00 cm
R2 = 6.00 cm
q1 = +6.00 nC
q2 = −9.00 nC
As we know,
The potential difference between the two shell's difference will be:
⇒ ![\Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]](https://tex.z-dn.net/?f=%5CDelta%20V%3DK%5B%28%5Cfrac%7Bq1%7D%7BR1%7D%2B%5Cfrac%7Bq2%7D%7BR2%7D%29-%28%5Cfrac%7Bq1%7D%7BR1%7D%20%2B%28%5Cfrac%7Bq2%7D%7BR2%7D%29%29%5D)
![=K[\frac{q1}{R2}-\frac{q1}{R1} ]](https://tex.z-dn.net/?f=%3DK%5B%5Cfrac%7Bq1%7D%7BR2%7D-%5Cfrac%7Bq1%7D%7BR1%7D%20%5D)
On substituting the values, we get
![=(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]](https://tex.z-dn.net/?f=%3D%289%5Ctimes%2010%5E9%29%5B%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.04%7D-%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.06%7D%5D)
Δ 
Answer:
I think the reflection of light off of a shiny surface is the answer... Hope this helps
Explanation:
Two forces F<span>1 and </span>F<span>2 act on the screw eye. The resultant force </span>FR<span> has a magnitude of 125 lb and the coordinate direction angles shown in (Figure 1) . Determine the magnitude of </span>F<span>2. Determine the coordinate direction angle </span>α<span>2 of </span>F<span>2. Determine the coordinate direction angle </span>β<span>2 of </span>F<span>2. Determine the coordinate direction angle </span>γ<span>2 of </span>F<span>2.</span>
the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period
Thank you
