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AleksandrR [38]
3 years ago
6

Two trees have perfectly straight trunks and are both growing perpendicular to the flat horizontal ground beneath them. The side

s of the trunks that face each other are separated by 1.1 m. A frisky squirrel makes three jumps in rapid succession. First, he leaps from the foot of one tree to a spot that is 0.9 m above the ground on the other tree. Then, he jumps back to the first tree, landing on it at a spot that is 1.7 m above the ground. Finally, he leaps to the other tree, now landing at a spot that is 2.3 m above the ground. What is the magnitude of the squirrel's displacement?
Physics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

2.55 m.

Explanation:

Displacement is the shortest distance between initial and final position . In the present case this distance forms the hypotenuse of the triangle having base equal to 1.1 m and perpendicular equal to 2.3 m .

Hypotenuse H then

H² = 1.1² + 2.3²

H = 2.55 m.

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The average velocity of the car for the whole journey is 69.57 km/h.

The given parameters:

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  • <em>Distance covered = 240 km at 75 km/h</em>
  • <em>time spent refueling, t₂ = 0.6 hr</em>
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The time spent by the before refueling is calculated as follows;

t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours

The time spent by the car for the remaining journey;

t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr

The total time of the journey is calculated as follows;

t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours

The average velocity of the car for the whole journey is calculated as follows;

v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h

Learn more about average velocity here: brainly.com/question/6504879

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