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AleksandrR [38]
3 years ago
6

Two trees have perfectly straight trunks and are both growing perpendicular to the flat horizontal ground beneath them. The side

s of the trunks that face each other are separated by 1.1 m. A frisky squirrel makes three jumps in rapid succession. First, he leaps from the foot of one tree to a spot that is 0.9 m above the ground on the other tree. Then, he jumps back to the first tree, landing on it at a spot that is 1.7 m above the ground. Finally, he leaps to the other tree, now landing at a spot that is 2.3 m above the ground. What is the magnitude of the squirrel's displacement?
Physics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

2.55 m.

Explanation:

Displacement is the shortest distance between initial and final position . In the present case this distance forms the hypotenuse of the triangle having base equal to 1.1 m and perpendicular equal to 2.3 m .

Hypotenuse H then

H² = 1.1² + 2.3²

H = 2.55 m.

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72 beats per minute

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Heart beat causes the flow of blood round the body. This heart beat can be felt as pulse in the wrist or neck carotid artery. The heart rate which is measured in beats per minute (BPM) is used to determine the number of heart beats per minute.

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Given that for 20 seconds, Bill had a total of 24 beats.

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Bas_tet [7]

Answer:

(a) Distance traveled = 75.3846 m

(b) Velocity of car at that instant will be 14 m/sec

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(a) According to second equation of motion we know that s=ut+\frac{1}{2}at^2

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t=10.769sec

So distance traveled s_c=s_t=7\times 10.769=75.3846m

(b) From second equation of motion we know that v = u+at

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