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AleksandrR [38]
3 years ago
6

Two trees have perfectly straight trunks and are both growing perpendicular to the flat horizontal ground beneath them. The side

s of the trunks that face each other are separated by 1.1 m. A frisky squirrel makes three jumps in rapid succession. First, he leaps from the foot of one tree to a spot that is 0.9 m above the ground on the other tree. Then, he jumps back to the first tree, landing on it at a spot that is 1.7 m above the ground. Finally, he leaps to the other tree, now landing at a spot that is 2.3 m above the ground. What is the magnitude of the squirrel's displacement?
Physics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

2.55 m.

Explanation:

Displacement is the shortest distance between initial and final position . In the present case this distance forms the hypotenuse of the triangle having base equal to 1.1 m and perpendicular equal to 2.3 m .

Hypotenuse H then

H² = 1.1² + 2.3²

H = 2.55 m.

You might be interested in
Inertia increases as an object's _________ increases.
sammy [17]

Answer:

A. Mass

Explanation:

Inertia of an object is the resistance of the object to any change in its state of motion: it means that if an object is at rest, it tends to stay at rest for inertia (unless a net force acts on it), and if it is moving, it tends to continue moving with the same velocity, for inertia.

The inertia also describes how difficult it is to stop/accelerate an object, and it is directly proportional to the mass of the object: in fact, the larger the mass of an object, the more difficult it is to change its state of motion, and this means it has greater inertia.

6 0
3 years ago
Read 2 more answers
12. A car is travelling at 30 m/s when the driver sees a red light in the distance and immediately applies the brakes. The car c
Triss [41]

Answer:

22.5 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 30 m/s

Time (t) = 1.5 s

Final velocity (v) = 0 m/s

Distance (s) =?

The distance to which the car move before stopping from the time the driver applied the brake can be obtained as follow:

s = (u + v)t/2

s = (30 + 0)1.5 / 2

s = (30 × 1.5) / 2

s = 45 / 2

s = 22.5 m

Thus, the car will move to a distance of 22.5 m before stopping from the time the driver applied the brake.

4 0
3 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.10 104 rad/s to an angular speed of 3.14
Anestetic [448]

Answer:

3.63 s

Explanation:

We can solve the problem by using the equivalent SUVAT equations for the angular motion.

To find the angular acceleration, we can use the following equation:

\omega_f^2 - \omega_i ^2 =2 \alpha \theta

where

\omega_f = 3.14\cdot 10^4 rad/s is the final angular speed

\omega_i = 1.10 \cdot 10^4 rad/s is the initial angular speed

\theta= 2.00 \cdot 10^4 rad is the angular distance covered

\alpha is the angular acceleration

Re-arranging the formula, we can find \alpha:

\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2

Now we want to know the time the bit takes starting from rest to reach a speed of \omega_f=7.85\cdot 10^4 rad/s. So, we can use the following equation:

\alpha = \frac{\omega_f-\omega_i}{t}

where:

\alpha=2.16\cdot 10^4 rad/s^2 is the angular acceleration

\omega_f = 7.85\cdot 10^4 rad/s is the final speed

\omega_i = 0 is the initial speed

t is the time

Re-arranging the equation, we can find the time:

t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s

4 0
3 years ago
Read 2 more answers
A soccer player pumps air into a soccer ball until no more air can be pushed inside. Describe the air inside the soccer ball com
inessss [21]

Answer:

the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.

Explanation:

This exercise asks to describe the inflation situation of a spherical fultball.

Initially the balloon is deflated, therefore the internal pressure is equal to the pressure of the air outside, atmospheric pressure, when it begins to inflate the balloon with a pump this creates a pressure in the inlet valve and as it is greater than the pressure inside, the air enters it, this is repeated in each filling cycle, manual pump.

When the ball is full we have two forces, the one created by the external walls and the one aired by the pressure of the pump, these forces are directed towards the inside, but the air molecules exert a pressure towards the outside, which translates into a force. When these two forces are equal, the pump is no longer able to continue introducing air into the balloon.

Consequently the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.

4 0
3 years ago
Name arleady three types of energy associated with a microwave
Elena L [17]
I'm pretty sure what you are trying to ask for is radiative energy, light energy, and electronic energy
<span>Radiative since the microwave is releasing radiation </span>
<span>Light since there is light inside the microwave.</span>
Electronic since it is plugged in and uses electricity.
<span>You can also use sound, but I don't think every microwave makes sound. </span>
6 0
2 years ago
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