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3 years ago

What is the difference between an element and a compound in terms of these models?(help asap)

Physics

1 answer:

Firdavs [7]3 years ago

4 0

The difference between elements and compounds is that compounds are made from different types of atoms while elements are made from only one type of atom

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Heat rash is caused by chemical exposure Truth or false

Harrizon [31]

Answer:

This is false.

Explanation:

Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.

3 0

2 years ago

Read 2 more answers

Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 60.7 A. The resistanc

lisov135 [29]

Answer:

a) The magnitude JJ of the current density for a copper cable is 5.91 × 10⁵A.m⁻²

b)The mass per unit length \lambdaλ for a copper cable is 0.757kg/m

c)The magnitude J of the current density for an aluminum cable is 3.5 × 10⁵A/m²

d)The mass per unit length \lambdaλ for an aluminum cable is 0.380kg/m

Explanation:

The expression for electric field of conductor is,

$E = \frac{V}{L}$

The general equation of voltage is,

V = iR

The expression for current density in term of electric field is,

$J = \frac{E}{p}$

Substitute (V/L) for E in the above equation of current density.

$J = \frac{V}{pL} ------(1)$

Substitute iR for V in equation (1)

$J = \frac{iR}{pL} ------(2)$

Substitute 1.69 × 10⁸ Ω .m for p

50A for i

0.200Ω.km⁻¹ for (R/L) in eqn (2)

$J = \frac{(50) (0.200\times 10^-^3) }{1.69 \times 10^-^8 } \\\\= 5.91 \times 10^5A.m^-^2$

The magnitude JJ of the current density for a copper cable is 5.91 × 10⁵A.m⁻²

b) The expression for resistivity of the conductor is,

$p = \frac{RA}{L}$

$A = \frac{pL}{R}$

The expression for mass density of copper is,

m = dV

where, V is the density of the copper.

Substitute AL for V in equation of the mass density of copper.

m=d(AL)

m/L = dA

λ is use for (m/L)

substitute,

pL/R for A and λ is use for (m/L) in the eqn above

$\lambda = d\frac{p}{\frac{R}{L} } ------(3)$

Substitute 0.200Ω.km⁻¹ for (R/L)

8960kgm⁻³ for d and 1.69 × 10⁸ Ω .m

$\lambda = (8960) \frac{(1.69 \times 10^-^8 }{0.200\times 10^-^3} \\\\= 0.757kg.m^-^1$

c) Using the equation (2) current density for aluminum cable is,

$J = \frac{iR}{pL}$

p is the resistivity of the aluminum cable.

Substitute 2.82 × 10⁻⁸Ω.m for p ,

50A for i and 0.200Ω.km⁻¹ for (R/L)

$J = \frac{(50)(0.200\times10^-^3) }{2.89\times 10^-^8} \\\\= 3.5 \times10^5A/m^2$

The magnitude J of the current density for an aluminum cable is 3.5 × 10⁵A/m²

d) Using the equation (3) mass per unit length for aluminum cable is,

$\lambda = d\frac{p}{\frac{R}{L} }$

p is the resistivity and is the density of the aluminum cable.

Substitute 0.200Ω.km⁻¹ for (R/L), 2700 for d and 2.82 × 10⁻⁸Ω.m for p

$\lambda = (2700) \frac{(2.82 \times 10^-^8) }{(0.200 \times 10^-^3) } \\\\= 0.380kg/m$

The mass per unit length \lambdaλ for an aluminum cable is 0.380kg/m

7 0

3 years ago

Read 2 more answers

Why do skiers often wear sunglasses while they are skiing

yulyashka [42]

There is a lot of glare off of the ice, due to the sun and it also is always good to have eye protection in case you fall face first :P

4 0

3 years ago

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Within the theory of G relativity what, exactly, is meant by " the speed of light WITHIN A VACUUM" ? & what does that have t

Ber [7]

The speed of light "within a vacuum" refers to the speed of electromagnetic radiation propagating in empty space, in the complete absence of matter. This is an important distinction because light travels slower in material media and the theory of relativity is concerned with the speed only in vacuum. In fact, the theory of relativity and the "speed of light" actually have nothing to do with light at all. The theory deals primarily with the relation between space and time and weaves them into an overarching structure called spacetime. So where does the "speed of light" fit into this? It turns out that in order to talk about space and time as different components of the same thing (spacetime) they must have the same units. That is, to get space (meters) and time (seconds) into similar units, there has to be a conversion factor. This turns out to be a velocity. Note that multiplying time by a velocity gives a unit conversion of
$seconds \times \frac{meters}{seconds} =meters$
This is why we can talk about lightyears. It's not a unit of time, but distance light travels in a year. We are now free to define distance as a unit of time because we have a way to convert them.
As it turns out light is not special in that it gets to travel faster than anything else. Firstly, other things travel that fast too (gravity and information to name two). But NO events or information can travel faster than this. Not because they are not allowed to beat light to the finish line---remember my claim that light has nothing to do with it. It's because this speed (called "c") converts space and time. A speed greater than c isn't unobtainable---it simply does not exist. Period. Just like I can't travel 10 meters without actually moving 10 meters, I cannot travel 10 meters without also "traveling" at least about 33 nanoseconds (about the time it takes light to get 10 meters) There is simply no way to get there in less time, anymore than there is a way to walk 10 meters by only walking 5.
We don't see this in our daily life because it is not obvious that space and time are intertwined this way. This is a result of our lives spent at such slow speeds relative to the things around us.
This is the fundamental part to the Special Theory of Relativity (what you called the "FIRST" part of the theory) Here is where Einstein laid out the idea of spacetime and the idea that events (information) itself propagates at a fixed speed that, unlike light, does not slow down in any medium. The idea that what is happening "now" for you is not the same thing as what is "now" for distant observers or observers that are moving relative to you. It's also where he proposed of a conversion factor between space and time, which turned out to be the speed of light in vacuum.

3 0

3 years ago

Plain electromagnetic wave (in air) has a frequency of 1 MHz and its B-field amplitude is 9 nT a. What is the wavelength in air?

Norma-Jean [14]

Answer:

Part a)

$\lambda = 300 m$