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OlgaM077 [116]
2 years ago
10

How many times larger than 3 x 10^4 is to 15 x 10^8

Mathematics
2 answers:
jek_recluse [69]2 years ago
6 0

Answer:

149970000

Step-by-step explanation:

1500000000-30000=149970000

sergiy2304 [10]2 years ago
5 0

Answer:

1499970000

Step-by-step explanation:

3 x 10^4 = 30,000

15 x 10^8 = 1500000000

1500000000 - 30,000 = 1499970000

You might be interested in
The spiders and ants in Aunt Mellys attic have a total of 152 legs and 22 heads. Spiders have 8 legs and ants have 6 legs. How m
Scorpion4ik [409]

Answer:

10 spiders and 12 ants

Step-by-step explanation:

You need to create two equations

s = # of spiders

a = # of ants

s + a = 22 heads

since each spider and ant has one head

8s + 6a = 152 legs

since every spider has 8 legs and every ant has 6

s + a = 22 can be turned into s = 22 - a

now use substitution

8(22 - a) + 6a = 152

176 - 8a + 6a = 152

176 - 2a = 152

24 = 2a

a = 12

now that you have the number of ants you can solve for the number of spiders

s + a = 22

s + 12 = 22

s = 10

6 0
2 years ago
The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo
qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

5 0
3 years ago
Chatty made this square picture. She wants to glue yarn around the border to make a frame. How much yarn does she need?
Romashka [77]

Answer:

60 inches

Step-by-step explanation:

s = 15 in

Perimeter of a Square = 4 s

                                     = 4 × 15

                                     = 60 in

∴Chatty needs 60 inches of yarn.

Hope that helps!!

Please mark as Brainliest!!

7 0
3 years ago
Read 2 more answers
your friend gives you a hint by telling you that a tank is located 10 units from the origin. tanks can be positioned only at who
Aleks [24]

Answer:

(10,0), -(10,0) (0,10) and (0.-10)

Step-by-step explanation:

7 0
3 years ago
In our solar system 6 of the 8 planets have moons what is the percentage of the planet have moons
umka2103 [35]
75% for your help:)…….
8 0
2 years ago
Read 2 more answers
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