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morpeh [17]
3 years ago
12

Which of the following is a possible set of quantum numbers for an electron

Chemistry
1 answer:
Alexxx [7]3 years ago
5 0
I am positive it is the last one!

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In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally i
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Answer:

A.

Carbon dioxide

Explanation:

In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally in Carbon dioxide

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2 years ago
THE CONSTANT MOVING OF AND HELP THE TEMPERATURES AROUND THE EARTH REMAIN ABOUT THE SAME AVERAGE
nika2105 [10]

New analysis through 2014 shows that temperature is once again rising at about the same pace as it did over the second half of the 20 th century. PRESS RELEASE. Using the data that were available at the time (through 2012), the last climate report from the Intergovernmental Panel on Climate Change concluded that there had been no statistically significant increase in global surface temperature

(I hope this helps you!)

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4 years ago
How many particles would one mole of NaCl have in solution​
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3 years ago
In the laboratory a student combines 40.6 mL of a 0.113 M copper(II) sulfate solution with 26.4 mL of a 0.329 M copper(II) iodid
Arisa [49]

Answer : The final concentration of copper(II) ion is, 0.198 M

Explanation :

First we have to calculate the moles of CuSO_4 and CuI_2.

\text{Moles of }CuSO_4=\text{Concentration of }CuSO_4\times \text{Volume of solution}

\text{Moles of }CuSO_4=0.113mol/L\times 0.0406L=0.00459mol

Moles of CuSO_4 = Moles of Cu^{2+} = 0.00459 mol

and,

\text{Moles of }CuI_2=\text{Concentration of }CuI_2\times \text{Volume of solution}

\text{Moles of }CuI_2=0.329mol/L\times 0.0264L=0.00869mol

Moles of CuI_2 = Moles of Cu^{2+} = 0.00869 mol

Now we have to calculate the total moles of copper(II) ion and total volume of solution.

Total moles copper(II) ion = 0.00459 mol + 0.00869 mol

Total moles copper(II) ion = 0.0133 mol

and,

Total volume of solution = 40.6 mL + 26.4 mL = 64.0 mL = 0.067 L    (1 L = 1000 mL)

Now we have to calculate the final concentration of copper(II) ion.

\text{Final concentration of copper(II) ion}=\frac{\text{Total moles}}{\text{Total volume}}

\text{Final concentration of copper(II) ion}=\frac{0.0133mol}{0.067L}=0.198mol/L=0.198M

Thus, the final concentration of copper(II) ion is, 0.198 M

5 0
3 years ago
Answer the question plssss
nataly862011 [7]

Answer: warmer because its an  exothermic reaction.

Explanation: the passage states as the products form thermal energy is absorbed thermal means heat also carbon dioxide creates bubbles

8 0
3 years ago
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