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Anna [14]
3 years ago
15

Can someone answer an easy chemistry question? A chemistry grad student measures the performance of the new pump in his lab. The

result is: z=16.0 kPa x mm^3 x s^-1 Convert z to mJ x s^-1 .
Chemistry
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

Z = 16.0\ kPa\ mm^3\ s^{-1} = 16.0\times 10^{-3}\ mJ.s^{-1}

Explanation:

Unit conversion is the multi-step process which involves the multiplication or the division by a specified numerical factor as well as the selection of the correct number of the significant digits and rounding.

There are various units in which physical parameters are expressed. In the given question qunatity is given in kPa\ mm^3\ s^{-1} which has to be converted to mJ.s^{-1}.

Further Explanation:

The given unit conversion includes two steps:

Step 1  

Conversion from kPa.mm^3.s^{-1} to Pa.m^3.s^{-1}

1kPa = 10^3\ Pa

1\ mm^3=10^{-9} m^3

Z = 16.0\ kPa\ mm^3\ s^{-1}

= 16.0\times (kPa\times \frac{10^3\ Pa}{1\ kPa} )\time (mm^3 \times \frac{10^{-9}\ m^3}{1\ mm^3} ).s^{-1}  

=16.0\times 10^{-6} Pa.m^3.s^{-1}

Step 2

Convesion from =16.0\times 10^{-6} Pa.m^3.s^{-1} to J.s^{-1}

1\ Pa=1 \frac{N}{m^2}

1 N.m = 1 J

=16.0\times 10^{-6} Pa.m^3.s^{-1} = 16.0 \times \frac{N}{m^2} .m^3 .s^{-1}
[tex]=16.0\times 10^{-6}\ J.s^{-1}

1\ J = 10^{3}\ mJ

16.0\times 10^{-6}\ J.s^{-1}=16.0\times (J\times \frac{10^3\ mJ}{1\ J}).s^{-1}

=16.0\times 10^{-3}\ mJ.s^{-1}

Learn More:

brainly.com/question/12586304  

brainly.com/question/10499702  

brainly.com/question/7892193  

Keywords:

Unit conversion, kPa, Pa, J,

ella [17]3 years ago
7 0
This problem requires our calculation to undergo the dimensional analysis approach. In this approach, you disregard the actual quantity and focus on the units of measurement. This helps us know the units of our final answer. 

First, let's ignore 16. Let's focus on converting the units kPa-mm³/s to mJ/s. The unit kPa stands for kiloPascals which is 1000 times greater than 1 Pa. The unit mJ, on the other hand, stands for millijoules, which is 1000 times lesser than Joules. The relationship between the two is that, Joules = Pa × m³. But since we want our final answer to be mJ, that would be equal to Pa×mm³. Since the original unit already contains mm³, all we have to do is convert kPa to Pa. 

16 kPa-mm³/s * (1000 Pa/1 kPa) = 16,000 Pa-mm³/s

Since Pa-mm³ is equal to mJ, the final conversion yields to 16,000 Pa-mm³/s.
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The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
While you are using a battery, the cell reaction is going a) forward, b) backward, c) at equilibrium, d) TEXASIN all possible
polet [3.4K]

Answer:Cell reaction is going forward.

Explanation:

For any chemical reaction to be spontaneous or to move in forward direction the ΔG ,the Gibbs free energy must be negative.

The cell potential of a battery is positive for a spontaneous reaction, so for a battery to give output its cell potential must be positive.

Thermodynamics and electro-chemistry are related in the following manner:

ΔG=-nFE

n=number of electrons involved

F=Faradays constant

E=cell pottential of battery

so from the above equation ΔG would only be negative when E cell that is the cell potential is positive.

For a battery which is being used its cell potential is positive and hence the ΔG would be negative. So the cell reaction occurring would be in forward direction as ΔG is negative.

when the cell potential Ecell is 0 then ΔG is also zero then the reaction occurring in battery would be at equilibrium.

When the cell potential Ecell is - then ΔG is positive and the reaction would be occurring backwards.

3 0
3 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2
kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

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The molarity of the NaOH solution is 0.076 M

4 0
3 years ago
In the compound MgCl2MgCl2, the subscript 2 indicates that
MatroZZZ [7]

 The subscript 2  indicate that  there are two atoms of chlorine  in the compound.

<u><em> Explanation</em></u>

 Subscript in the chemical formula indicate  the number of atoms  of the element immediately  before the subscript.

In MgCl₂  there are two(2)  atoms of chlorine  since Subscript 2 is immediately  after chlorine.

3 0
3 years ago
I need the answer to this asap!! please explain
kumpel [21]

Answer:

See explanation

Explanation:

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This now shows us that the equation as written in the question is wrong. Since the equation for the reaction of calcium carbide and water as shown in the question is wrong, the equation can not be balanced.

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