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Anna [14]
3 years ago
15

Can someone answer an easy chemistry question? A chemistry grad student measures the performance of the new pump in his lab. The

result is: z=16.0 kPa x mm^3 x s^-1 Convert z to mJ x s^-1 .
Chemistry
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

Z = 16.0\ kPa\ mm^3\ s^{-1} = 16.0\times 10^{-3}\ mJ.s^{-1}

Explanation:

Unit conversion is the multi-step process which involves the multiplication or the division by a specified numerical factor as well as the selection of the correct number of the significant digits and rounding.

There are various units in which physical parameters are expressed. In the given question qunatity is given in kPa\ mm^3\ s^{-1} which has to be converted to mJ.s^{-1}.

Further Explanation:

The given unit conversion includes two steps:

Step 1  

Conversion from kPa.mm^3.s^{-1} to Pa.m^3.s^{-1}

1kPa = 10^3\ Pa

1\ mm^3=10^{-9} m^3

Z = 16.0\ kPa\ mm^3\ s^{-1}

= 16.0\times (kPa\times \frac{10^3\ Pa}{1\ kPa} )\time (mm^3 \times \frac{10^{-9}\ m^3}{1\ mm^3} ).s^{-1}  

=16.0\times 10^{-6} Pa.m^3.s^{-1}

Step 2

Convesion from =16.0\times 10^{-6} Pa.m^3.s^{-1} to J.s^{-1}

1\ Pa=1 \frac{N}{m^2}

1 N.m = 1 J

=16.0\times 10^{-6} Pa.m^3.s^{-1} = 16.0 \times \frac{N}{m^2} .m^3 .s^{-1}
[tex]=16.0\times 10^{-6}\ J.s^{-1}

1\ J = 10^{3}\ mJ

16.0\times 10^{-6}\ J.s^{-1}=16.0\times (J\times \frac{10^3\ mJ}{1\ J}).s^{-1}

=16.0\times 10^{-3}\ mJ.s^{-1}

Learn More:

brainly.com/question/12586304  

brainly.com/question/10499702  

brainly.com/question/7892193  

Keywords:

Unit conversion, kPa, Pa, J,

ella [17]3 years ago
7 0
This problem requires our calculation to undergo the dimensional analysis approach. In this approach, you disregard the actual quantity and focus on the units of measurement. This helps us know the units of our final answer. 

First, let's ignore 16. Let's focus on converting the units kPa-mm³/s to mJ/s. The unit kPa stands for kiloPascals which is 1000 times greater than 1 Pa. The unit mJ, on the other hand, stands for millijoules, which is 1000 times lesser than Joules. The relationship between the two is that, Joules = Pa × m³. But since we want our final answer to be mJ, that would be equal to Pa×mm³. Since the original unit already contains mm³, all we have to do is convert kPa to Pa. 

16 kPa-mm³/s * (1000 Pa/1 kPa) = 16,000 Pa-mm³/s

Since Pa-mm³ is equal to mJ, the final conversion yields to 16,000 Pa-mm³/s.
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How many atoms of gold are in a pure gold coin weighing 12.0g?
grigory [225]
12.0g x 1 mol / 63.546g = 0.188839581mol 

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3 years ago
During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

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3 years ago
How many moles are in 68 grams of copper (II) hydroxide, Cu(OH)2
jarptica [38.1K]

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What is the molarity of a solution that contains 1000.0 mg of AgNO3 that has been dissolved in 500 mL of water
Vaselesa [24]

0.012moldm⁻³

Explanation:

Given parameters:

Mass of AgNO₃  = 1000mg

Volume of water = 500mL

Unknown:

Molarity of solution  = ?

Solution:

The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.

 Molarity = \frac{xnumber of moles}{Volume}

 

Number of moles of AgNO₃  = ?

   Number of moles = \frac{mass}{molar mass}

Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol

   convert mass to g;

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   convert the given volume to dm³;

       1000mL  = 1dm³;

        500mL = 0.5dm³

Now solve;

  Molarity = \frac{0.00588}{0.5}  = 0.012moldm⁻³

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

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