The mole fraction of the 2.2 molal solution whose solvent is naphthalene is 0.28.
Using the relation;
molality = mole fraction × 1000/MA
Where MA = molar mass of the solvent
We know from the question that the molaity of the solution is 2.2 molal
Making the mole fraction the subject of the formula;
mole fraction = molality × MA/1000
MA = 128 g/mol
mole fraction = 2.2 × 128/1000
Mole fraction = 0.28
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Answer:
1. Exothermic.
2. Yes, released.
3. 38.65KJ of heat is released.
Explanation:
The equation for the reaction is given below:
2NO2 —> N2O4...... ΔH = –55.3KJ
1. The sign of the enthalpy change, ΔH tells whether the reaction is endothermic or exothermic. Since the sign of the enthalpy change, ΔH is negative, the reaction is exothermic.
2. The negative sign indicate that heat is released to the surrounding. Since the reaction is generally an exothermic reaction, 64.3g of NO2 will also release heat to the surroundings.
3. Molar mass of NO2 = 14 + (16x2) = 46g/mol
Mass of NO2 from the balanced equation = 2 x 46 = 92g.
From the balanced equation above:
92g of NO2 reacted to release –55.3KJ of heat.
Therefore, 64.3g of NO2 will react to release = (64.3 x –55.3)/92 = 38.65KJ of heat.
Therefore, 38.65KJ of heat is released.
Is similar to 3 an you nedd múltiple by 5 and you get 15 for the result
Answer:
Explanation:
The dilution formula is
s₁ v₁ = s₂ v₂
s₁ = .0043
v₁= 2 mL
v₂ = 100 mL
s₂ = ?
putting the values
.0043 x 2 = s₂ x 100
s₂ = .000086 = 86.0 x 10⁻⁶