C+O2----> CO2
8.00g 10.9 g
8.00g C*1 molC/12.0g C= 0.667 mol C
10.2g CO2*1mol/(12.0+2*16.0)=0.232 mol CO2 actual yield
0.667 mol C gives 0.667 mol CO2 theoretical yield
% yield = (actual yield/theoretical yield)*100%=
=(0.232 mol CO2/0.667 mol CO2)*100%= 34.9%
Because you don't want glass jars because they will break. Plastic containers is the best thing to use
Answer:
P2 = P1*n2 / n1
=1.02 atm *0.008 moles / 0.00113 moles
= 7.22 atm
∴the new pressure will be 7.22 atm
Explanation:
Whales eat fish and their bigger
Answer:
See Explanation
Explanation:
Given:
moles M = 0.600 mole
moles F = excess (for rxn stoichiometry)
Formula Weight (F.Wt.) of F = 19 grams/mole (from Periodic Table)
Yield in grams = 46.8 grams (assuming theoritical yield)
Rxn: M + F₂ => MF₂
0.600mol Excess 0.600mol (1:1 rxn ratio for M:MF₂)
a. moles of F in MF₂ = 2(0.600) moles F = 1.2 moles F
b. mole weight MF₂ = 46.8g/0.600mol = 78g/mole
F.Wt. MF₂ = F.Wt. M + 2(F.Wt. F)
=> mass M = F.Wt. M = [F.Wt. MF₂ - 2(F.Wt. F)] = 78g/mol. - 2(19g/mol.)
= (78 - 38) grams/mole = 40 grams/mole
c. Calcium (Ca) has F.Wt. = 40 grams/mole (compared to Calcium on Periodic Table.
