The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:
203 80 Hg → 203 81 + 0 -1 e
<h3>What is beta decay?</h3>
Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.
Beta particle is characterized by the possession of mass number 0 and atomic number -1.
This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:
203 80 Hg → 203 81 Tl + 0 -1 e
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The required mass of calcium bromide is 35.98 grams.
<h3>What is molarity?</h3>
Molarity is any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V, where
- M = molarity = 4M
- V = volume = 45mL = 0.045L
Moles will be calculated by using the above equation as:
n = (4)(0.045) = 0.18 mole
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g
Hence required mass of CaBr₂ is 35.98 grams.
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Answer: 1 × 10−2 M
Explanation: Kw is known as the constant of water dissociation and its value is found to be 
. It is the product of the concentration of [H3O+] and [OH -] ions .
Dissociation of water can be represented by -
Kw = [H3O+] [OH -]
As we know that pKw = - log Kw,
Thus pKw = 14
pOH = - log OH- = - log (10^{-12}) = 12
and pKw = pH + pOH
14 = pH + 12
pH = 14 - 12 = 2
pH = -log H3O+
2 = -log H3O+
Therefore, [H3O+] = 1 × 10−2 M
Trueeeeeeeeeeeeeeeee!!!!!
