Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is 
(b) The normal boiling point of water (J·K−1·mol−1) is 
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
= 
= 
→ phases
ΔH → enthalpy of transition
T → temperature transition
=
= 
( 
is the enthalpy of fusion of water)
=
(b) 
= 
(
is the enthalpy of vaporization)
=
(c) 
=
°
°![C)]](https://tex.z-dn.net/?f=C%29%5D)
= 
°
°
ΔT
°
°
= 109J/mole
Appropriate symbol for an isotope of potassium - 39 corresponding to the isotope notion r A ZX
Potassium outermost electron occupy "4s" orbital
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
The correct answer is D<span>) remains hazardous for a long time. Nuclear waste stays radioactive for many centuries.
</span>
This is generally buried underground, so it does not cause significant air pollution, greenhouse effect, or acid rain<span>. These three are mostly caused by particulate matter or greenhouse gases that are emitted into the atmosphere
</span>
