Given :
On a shelf sits a bottle of NaCl solutions with a molar concentration of 2.50 M and a total volume of 300 mL. If 15.0 mL of the solution is added to 985 mL of pure water .
To Find :
The molar concentration of NaCl in the new solution.
Solution :
Molarity M is given by :

Now , 1000 ml of NaCl contains 2.5 moles of NaCl .
So , 15 ml of NaCl contains :

New , volume V = 15 + 985 = 1000 ml = 1 L .
So , putting value of n and V in above equation :

Therefore , the molar concentration of NaCl in the new solution is 0.0375 M .
Hence , this is the required solution .
The answer is c I know because I did did yesterday
Adding more hydrogen gas to the system or decreasing the volume of the container that the system is in. Le Chatelier's principle supports this.
Full electron configuration of barium: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s2
Answer:
answer is 12.18
Explanation:
(C2H5NH2, Kb = 5.6 x 10-4.)