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damaskus [11]
3 years ago
5

What information can you determine from the coefficients of this balanced chemical equation?

Physics
1 answer:
V125BC [204]3 years ago
6 0
HCl would be the limiting factor... but idk of thats what youre looking for
You might be interested in
Nonrenewable Energy is technically not completely nonrenewable. Why is this?
torisob [31]

Answer:

The 2nd one

Explanation:

It takes a long time to replenish.. ex:- fossil fuel

5 0
3 years ago
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance
FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0
3 years ago
What information do you need to describe an object's location
stira [4]
longitude and latitude<span />
4 0
3 years ago
The earth travels around the sun once a year in an approximately circular orbit whose radius is 1.50x10^11 m. From this data det
seraphim [82]
(a) Determine the circumference of the Earth through the equation,
            C = 2πr
Substituting the known values, 
           C = 2π(1.50 x 10¹¹ m)
             C = 9.424 x 10¹¹ m

Then, divide the answer by time which is given to a year which is equal to 31536000 s. 
          orbital speed = (9.424 x 10¹¹ m)/31536000 s

               orbital speed = 29883.307 m/s

Hence, the orbital speed of the Earth is ~29883.307 m/s.

(b) The mass of the sun is ~1.9891 x 10³⁰ kg. 
8 0
4 years ago
A toy car runs off the edge of a table that is 2.225 m high. If the car lands 0.400 m away from the base of the table, how fast
ruslelena [56]

Answer:

0.594 m/s

Explanation:

First, find the time it takes to land.

Given, in the y direction:

Δy = 2.225 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(2.225 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.674 s

Next, find the horizontal velocity.

Given, in the x direction:

Δx = 0.400 m

a = 0 m/s²

t = 0.674 s

Find: v₀

Δx = v₀ t + ½ at²

(0.400 m) = v₀ (0.674 s) + ½ (0 m/s²) (0.674 s)²

v₀ = 0.594 m/s

8 0
3 years ago
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