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Nataly_w [17]
3 years ago
14

Which statement describes absolute and apparent brightness?

Physics
2 answers:
maria [59]3 years ago
8 0

♡ hello there ヾ(°∇° ) ♡

   Your answer is...

       ★ ... <u>D</u> !!! ★

×║hope this helps,║×

➶ have a nice day! ➷

       ↬ ɢᴏᴛʜɪx ♡

xeze [42]3 years ago
7 0

The answer is: Absolute brightness is the actual amount of light produced by the star, whereas apparent brightness changes with distance from the observer. Hope this helps, and have a great day

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Refraction is the change in direction of a wave.
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4 years ago
A) Charge q1 = +5.60 nC is on the x-axis at x = 0 and an unknown charge q2 is on the x-axis at x = -4.00 cm. The total electric
jeka94

Answer:

a) F₃₁ = 63.0 μN  

b) F₃₂ = - 14.0 μN

c) q₂ = - 5.0 nC

Explanation:

a)

  • Assuming that the three charges can be taken as point charges, the forces between them must obey Coulomb's Law, and can be found independent each other, applying the superposition principle.
  • So, we can find the force that q₁ exerts along the x-axis on q₃, as follows:

       F_{31} =\frac{k*q_{1}*q_{3} }{r_{13}^{2}} = \frac{9e9Nm2/C2*5.6e-9C*2.0e-9C}{(0.04m)^{2}}  = 63.0 \mu N   (1)

b)

  • Since total force exerted by q₁ and q₂ on q₃ is 49.0 μN, we can find the force exerted only by q₂ (which is along the x-axis only too) just by difference, as follows:

      F_{32} = F_{3} - F_{31}  = 49.0\mu N  - 63.0\mu N = -14.0 \mu N  (2)

c)

  • Finally, in order to find the value of q₂, as we know the value and sign of F₃₂, we can apply again the Coulomb's Law, solving for q₂, as follows:

      q_{2}  = \frac{F_{32} * r_{23}^{2} }{k*q_{3}} = \frac{(-14\mu N)*(0.08m)^{2}}{9e9Nm2/C2* 2 nC} = - 5 nC  (3)

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Both are at the side of the spectrum that has the lower frequency

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Answer:

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it means that it's a vector quantity.

Hope this helps ;) ❤❤❤

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