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3 years ago

Are the following solutions acidic, basic, ot neutral.

Chemistry

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer:

1) Basic

2) Basic

3) Acidic

Explanation:

pH of a solution is a measure of the H3O+ ions in the solution and hence reflects its acidity.

$pH = -log[H3O+]$

Solutions are classified as acidic, basic or neutral based on the pH range

-pH < 7, acidic

- pH = 7, neutral

- pH > 7, basic

1) [H3O+] = 2.5*10^-9M

$pH = -log[H3O+]=-log[2.5*10^{-9}]=8.60$

Since pH > 7, solution is basic

2)[OH-] = 1.6*10^-2M

$pOH = -log[OH-]=-log[1.6*10^{-2}]=1.80$

pH = 14 - pOH = 14 - 1.80 =12.2

Since pH > 7, solution is basic

3) [H3O+] = 7.9*10^-3M

$pH = -log[H3O+]=-log[7.9*10^{-3}]=2.10$

Since pH < 7, solution is acidic

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Answer:

–36 KJ.

Explanation:

The equation for the reaction is given below:

2B + C —› D + E. ΔH = – 24 KJ

From the equation above,

1 mole of D required – 24 KJ of energy.

Now, we shall determine the energy change associated with 1.5 moles of D.

This can be obtained as illustrated below:

From the equation above,

1 mole of D required – 24 KJ of energy

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3 years ago

Calcium carbonate decomposes into calcium oxide and carbon dioxide. If 530 g of calcium carbonate decomposes, how many grams of

Rudik [331]

Answer:

233 g

Explanation:

Let's consider the following reaction.

CaCO₃ → CaO + CO₂

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The products of the unbalanced reaction are as follows:

Ba(OH)₂ (aq) + H₃PO₄(aq) → Ba₃(PO₄)₂(s) + H₂O(l)

This is an acid base reaction where Ba(OH)₂ is the base and H₃PO₄ is the acid. Acid base reaction is also known as neutralization reaction where the acid and base react with each other to form salt and water. In this reaction Ba₃(PO₄)₂ is the salt. Also barium phosphate (Ba₃(PO₄)₂) is insoluble in water and forms a solid precipitate.

The balanced reaction is as follows:

3Ba(OH)₂ (aq) + 2H₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6H₂O(l)

There are three Ba from Ba₃(PO₄)₂ on the product side of the equation, so to balance 3 coefficient was placed before Ba(OH)₂. Similarly, 2 coefficient was placed before H₃PO₄ on the reactant side to balance the two phosphate from Ba₃(PO₄)₂ on the product side. Finally, 6 coefficient was placed before H₂O on the product side, to balance the number of H and O atoms on both side of the equation.

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