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myrzilka [38]
3 years ago
13

Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of microgra

ms. How many milligrams are in a dose labeled 125 µg? View Available Hint(s) Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of micrograms. How many milligrams are in a dose labeled 125 µg? 1.25 x 105 mg 0.125 mg 1.25 x 10?4 mg 1.25 x 102 mg
Chemistry
1 answer:
leonid [27]3 years ago
4 0

Answer:

0.125 mg

Explanation:

<em>The correct answer would be 0.125 mg</em>

<u>According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.</u>

milligram = 10^{-3}

microgram = 10^{-6}

Hence,

1 milligram = 1000 micrograms or 1 microgram = 10^{-3} milligram

Therefore, 125 micrograms will be:

  125/1000 = 0.125 milligram

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This question is about iron three of the raw material added to a blast furnace used to extract iron from henatite are coke hemat
IrinaVladis [17]

Answer: The fourth material that is added to the blast furnace is HOT AIR which provides OXYGEN for used for combustion of carbon (Coke).

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7 0
2 years ago
The _________ __________ is the bottom number on each element?
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7 0
3 years ago
A space air is at a temperature of 75 oF, and the relative humidity (RH) is 45%. Using calculations, find: (a) the partial press
earnstyle [38]

Answer:

A) Partial Pressure of dry air = 13.32 KPa

Partial Pressure of water vapour = 1.332 KPa

B) Humidity ratio; X = 0.0691

C) V_p = 0.8384 m³/Kg

Explanation:

A) We are given;

Temperature = 75°F

Relative Humidity = 45%

Now,to calculate the partial pressure, we will use the relationship;

Relative Humidity = (Partial Pressure/Vapour Pressure) × 100%

Making partial pressure the subject;

Partial Pressure = Relative Humidity × Vapour Pressure/100%

From the first table attached, at temperature of 75°F, the vapor pressure is 29.6 × 10^(-3) bar = 29.6 KPa

Thus;

Partial Pressure of dry air = (45 × 29.6)/100

Partial Pressure of dry air = 13.32 KPa

From online values, vapour pressure of water vapour at 75°F = 2.96 KPa

Thus;

Partial Pressure of water vapour = (45 × 2.96)/100 = 1.332 KPa

B) humidity ratio of moist air is given as;

X = 0.62198 pw / (pa - pw)  

where;

pw = partial pressure of the water vapor in moist air

pa = atmospheric pressure of the moist air

Thus;

X = (0.62198 × 1.332)/(13.32 - 1.332)  

X = 0.0691

C) Formula for moist air specific volume is;

V_p = (1 + (xRw/Ra) × RaT/p

Where;

V_p is specific volume

T is temperature = 75°F = 297.039 K

p is barometric pressure which in this case is standard sea level pressure = 101.325 KPa

pw is partial pressure of the water vapor in moist air = 1.332 KPa

Rw is individual gas constant for water = 0.4614 KJ/Kg.K

Ra is individual gas constant for air = 0.2869 KJ/Kg.K

V_p = (1 + (0.0691 * 0.4614/0.2869)) × 0.286.9 * 297.039/101.325

V_p = 0.8384 m³/Kg

6 0
3 years ago
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