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julsineya [31]
3 years ago
10

Anyone know this????

Chemistry
1 answer:
Anastasy [175]3 years ago
3 0
The correct answer is the first one
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Given the following equation formats, which form matches a single replacement
Ber [7]

Answer:

The answer is c. A + BC → AC + B

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3 years ago
It takes 5.54 mL of a 2.18 M NaOH solution to neutralize 6.19 mL of an HCl solution. What is the concentration of the HCl soluti
svetlana [45]

Answer:

2 M

Explanation:

NaOH + HCl --> NaCl + H2O,

5.54 mL = .00545 L,

If we consider 2.18 M, M [molarity] = mol/L, so we have 2.18 mol/L. From this we can get the moles of NaOH.

.00545 L *  2.18 mol/L ≈ .0121 mol

The concentration of HCl can be found from the following:

.0121 mol = .00619(x) [where x = concentration of HCl]

x = 1.955 M ≈ 2 M

We equate the two as we require the same amount in order to neutralize the base.

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3 years ago
what would be the observation when you dipp magnesium hydroxide in a blue litmus paper and a red litmus paper. also what would b
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Answer:

red litmus will turn blue

blue litmus will remain blue

Explanation:

magnesium hydroxide is a base therefore turns red litmus paper blue

4 0
2 years ago
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6. What do the data tell you about your hypothesin?
Vikentia [17]

Answer:I like cheese

Explanation:do you like cheese

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In 1987 the first substance to act as a superconductor at a temperature above that of liquid nitrogen (77 k) was discovered. the
Mila [183]

 

The molar mass of the elements are:

Yttrium (Y) = 88.91 g / mol

Barium (Ba) = 137.33 g / mol

Copper (Cu) = 63.55 g / mol

Oxygen (O) = 16 g / mol

 

Calculating for the molar mass of YBa2Cu3O7:

YBa2Cu3O7 = 88.91 + 2(137.33) + 3(63.55) + 7(16) = 666.22 g / mol

 

The masses of the elements in 1 mole of YBa2Cu3O7 are:

Yttrium (Y) = 88.91 g / mol (1 mole) = 88.91 g

Barium (Ba) = 137.33 g / mol (2 mole) = 274.66 g

Copper (Cu) = 63.55 g / mol (3 mole) = 190.65 g

Oxygen (O) = 16 g / mol (7 mole) = 112 g

 

We now calculate for the percent composition by mass of each element:

% Y = 88.91 g / 666.22 g = 13.35%

% Ba = 274.66 g / 666.22 g = 41.23%

%Cu = 190.65 g / 666.22 g = 28.62%

<span>%O = 112 g / 666.22 g = 16.81%</span>

3 0
3 years ago
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