Answer:
% I = 0.083 %
Explanation:
- C6H5COOH + NaOH ↔ NaC6H5CO2 + H2O
∴ M C6H5COOH = 0.18 mol/L
∴ M NaC6H5CO2 = 0.10 mo/L
- % ion = ( { H3O+ ] / initial acid concentration ) * 100
⇒ C6H5COOH ↔ H3O+ + C6H5COO-
⇒ NaC6H5CO2 ↔ Na+ + C6H5COO-
∴ Ka = 6.4 E-5 = ( [ H3O+ ] * [ C6H5COO- ] ) / [ C6H5COOH ]
Ka value taken from the literature
mass balance
⇒ 0.18 + 0.1 = [ C6H5COOH ] + [ C6H5COO- ]
⇒ [ C6H5COOH ] = 0.28 - [ C6H5COO- ] ........(1)
charge balance:
⇒ [ H3O+ ] + [ Na+ ] = [ C6H5COO- ]
∴ [ Na+ ] ≅ M NaC6H5CO2 = 0.1 M
⇒ [ C6H5COO- ] = [ H3O+ ] + 0.1..............(2)
(1) and (2) in Ka:
⇒ 6.4 E-5 = ( [ H3O+ ] * ( [ H3O+ ] + 0.1 ) / ( 0.28 - ( [ H3O+ ] + 0.1 ) )
⇒ 6.4 E-5 = [ H3O+ ]² + 0.1 [H3O+ ] / ( 0.18 - [ H3O+ ] )
⇒ 1.17 E-5 - 6.5 E-5 [ H3O+ ] = [ H3O+ ]² + 0.1 [ H3O+ ]
⇒ [ H3O+ ]² + 0.1 [ H3O+ ] - 1.17 E-5 = 0
⇒ [ H3O+ ] = 1.493 E-4 M
⇒ % I = ( 1.493 E-4 / 0.18 ) * 100 = 0.083 %
Answer:
The steepness of a hill is called a slope. The same goes for the steepness of a line. The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run.
Answer:
B
Explanation:
Because the iron is wrong because of the contemplation of bisectors interfere with the question making it B.
Answer:
45.3°C
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 82KPa
Initial temperature (T1) = 26°C
Final pressure (P2) = 87.3KPa.
Final temperature (T2) =.?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T1) = 26°C
Initial temperature (T1) = 26°C + 273 = 299K.
Step 3:
Determination of the new temperature of the gas. This can be obtained as follow:
P1/T1 = P2/T2
82/299 = 87.3/T2
Cross multiply to express in linear form
82 x T2 = 299 x 87.3
Divide both side by 82
T2 = (299 x 87.3) /82
T2 = 318.3K
Step 4:
Conversion of 318.3K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T(K) = 318.3K
T(°C) = 318.3 – 273
T(°C) = 45.3°C.
Therefore, the new temperature of the gas in th tire is 45.3°C
From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.
<h3>What is stoichiometry?</h3>
Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.
Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles
Molar mass of carbon monoxide = 12 + 16 = 28g/mol
We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.
If 1 mole of a gas occupies 22.4 L
2 moles of a gas occupies 2 moles * 22.4 L/1 mole
= 44.8 L
Learn more about stoichiometry:brainly.com/question/9743981
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