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NNADVOKAT [17]
3 years ago
10

How many grams of glucose are in 11.5 moles?

Chemistry
1 answer:
qaws [65]3 years ago
5 0

There are 2071.4662 grams of glucose in 11.5 moles.

Per 1 mole there are 180.15588 grams of glucose. 180.5588 x 11.5 =2076.4262

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The state of matter that has molecules with the least random molecular arrangement:
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Gas. Molecules in gas are able to move and vibrate around each other more freely than the molecules in liquids and/or solids due to the great amount of space in between them. Hope this helps! :)
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3 years ago
A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution
tresset_1 [31]

Answer:

.125 M

Explanation:

.15 M/L   * .125 L = .01875 moles

now dilute to 150 cc  (by adding 25 cc)

.01875M / (150/1000) = .125M

5 0
2 years ago
When 4.15 grams of silver nitrate is reacted with 1.11 grams of iron(III) chloride, which best represents the amount of silver c
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Answer:

The mass of silver chloride produced = 2.202 g

Explanation:

Equation of the reaction is given below

3AgNO₃(aq) + FeCl₃(aq) ----> 3AgCl(s) + Fe(NO₃)₃(aq)

molar mass of AgNO₃ = 170 g/mol

molar mass of FeCl₃ = 233.5 g/mol

molar mass of AgCl = 143.5 g/mol

3 moles of silver nitrate reacts with 1 mole of iron (iii) chloride to give 3 moles of silver nitrate

4.15 grams of AgNO₃ = 4.15/170 = 0.0244 moles of AgNO₃

1.11 grams of FeCl₃ = 1.11/233.5 = 0.0047 moles of FeCl₃

mole ratio of AgNO₃ to FeCl₃ = 0.0244/0.0047 = 5 : 1

therefore, FeCl₃ is the limiting reactant

0.0047 moles of FeCl₃ reacting will produce 0.0047 *  3 moles of AgCl = 0.0141 moles of AgCl

0.0141 moles of AgCl = 0.0141 * 143.5 g of AgCl = 2.02 g of AgCl =

Therefore mass of silver chloride produced = 2.202 g

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3 years ago
An unknown gas is contained in a sealed container. Over time, the gas is gradually cooled until it becomes a solid. Determine wh
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Answer:D molecular attraction increases as temp decreases

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