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3 years ago

What is the quotient?

Mathematics

1 answer:

cupoosta [38]3 years ago

5 0

Answer:

D) 5 7/9

Work Shown:

-52/-9 = 5 7/9 = 5.7777777778

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Heyyyy I really need help with dis. If u can please answer and explain

Arisa [49]

Answer:

This should help

Step-by-step explanation:

4 0

3 years ago

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A cuboid with dimensions 45 cm by 16 cm by 12 cm is cut to form smaller cubes of

LenKa [72]

Answer:

<u>135 cubes</u>

Step-by-step explanation:

Volume of cuboid :

45 x 16 x 12
720 x 12
8,640 cm³

Volume of a small cube :

(4)³
64 cm³

Number of cubes :

n = 8,640/64
n = <u>135 cubes</u>

4 0

2 years ago

How do you graph it on a line

Aleonysh [2.5K]

In order to draw x ≤ -10 on a number line, first draw a closed dot at -10. This is because we have a ≤ and not a <. If we had a <, it would be an open dot.

Next, since we want x to be smaller, draw an arrow pointing towards all numbers that are smaller. This arrow would point to the left.

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3 years ago

The prism below is made of cubes which measure 1/3 of an inch on one side what is the volume

EastWind [94]

Answer:

Volume of rectangular prism = 10/9 inch³

Step-by-step explanation:

Given:

Size of each cube = 1/3 inch

Find:

Volume of rectangular prism

Computation:

Length of rectangular prism = 2 x [1/3]

Length of rectangular prism = 2/3 inch

Width of rectangular prism = 3 x [1/3]

Width of rectangular prism = 3/3

Width of rectangular prism = 1 inch

Height of rectangular prism = 5 x [1/3]

Height of rectangular prism = 5/3 inch

Volume of rectangular prism = Length x Width X Height

Volume of rectangular prism = [2/3] x [1] x [5/3]

Volume of rectangular prism = 10/9 inch³

7 0

3 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago