a = F/(m1+m2)
1.2 = F/48,000
F = 57,600N
a = F/(m1+m3)
a = 57,600/24,000
a = 2.4 m/s^2
Answer:
0.07756 m
Explanation:
Given mass of object =0.20 kg
spring constant = 120 n/m
maximum speed = 1.9 m/sec
We have to find the amplitude of the motion
We know that maximum speed of the object when it is in harmonic motion is given by
where A is amplitude and
is angular velocity
Angular velocity is given by
where k is spring constant and m is mass
So 

The x component of the force is 8.4N * cos(31°) = 7.2N (2 s.f.)