In this problem, only the following pair of sentences describe people with same velocity: Valerie rides her bike south at 8 kilometers per hour. Owen jogs south at 8 kilometers per hour. In fact, both Valerie and Owen are moving at same speed (8 km per hour) in the same direction (south), so they have same velocity.
The circular but relatively flat portion of the galaxy is the Disk
Answer:
a) 1321.45 N
b) 1321.45 N
c) 2.66 m/s^2
d) 2.21*10^-22 m/s^2
Explanation:
Hello!
First of all, we need to remember the gravitational law:
Were
G = 6.67428*10^-11 N(m/kg)^2
m1 and m2 are the masses of the objects
r is the distance between the objects.
In the present case
m1 = earth's mass = 5.9742*10^24 kg
m2 = 497 kg
r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m
Replacing all these values on the gravitational law, we get:
F = 1321.45 N
a) and b)
Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.
The acceleration can be calculated dividing the force by the mass of the object
c)
a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)
a_satellite = 2.66 m/s^2
d)
a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)
a_earth = 2.21*10^-22 m/s^2
Explanation:
A ball is thrown straight upward and falls back to Earth. It means that it is coming to the initial position. Displacement is given by the difference of final position and initial position. The displacement of the ball will be 0. As a result velocity will be 0.
Acceleration is equal to the rate of change of velocity. So, its acceleration is also equal to 0.
Hence, displacement, velocity and acceleration are zero.
Given:
altitude, x = 1 mile
speed, v = 560 mi/h
distance from the station, x = 4 mi
Solution:
To find the rate,
Now, from the right angle triangle in fig 1.
Applying pythagoras theorem:
differentiating the above eqn w.r.t 't' :
(1)
Now, putting values in eqn (1):
The rate at which distance from plane to station is increasing is: