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4 years ago

The equations 2x+7=3 and bx-10=-2 have the same solution for x. Find the value of b.

Mathematics

1 answer:

White raven [17]4 years ago

4 0

Solve both equations for x:

2x+7 = 3

2x = -4

x = -2

Plug x into the equation which contains b:

b(-2) -10 = -2

-2b = 8

b = -4

Answer:

b = -4

x = -2

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Let f(x)=x+8and g(x)=x^2-6x-7. Find f(g(2))

posledela

The answer is a. -7

1. Find g(2).

2. Find f(g(2)).

g(x) = x² - 6x - 7

x = 2 ⇒ g(2) = ?

g(2) = 2² - 6·2 - 7 = 4 - 12 - 7 = -15

2. f(x) = x + 8

g(2) = -15

f(g(2)) = f(-15) = -15 + 8 = -7

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3 years ago

Adam's father drove his car at a speed of 65.2 miles per hour to go to a business conference. If his trip took 1.8 hours, how ma

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3 years ago

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MrRa [10]

Im confused on what your trying to ask...

6 0

3 years ago

6x-2y=24 how do u solve for y

Tatiana [17]

It's Diophantine equation.
First, we need to found gcd(6,(-2)):
6=2*3
(-2)=(-1)*2

So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
$\frac{24}{2} =12$
So, we can solve it.

Now is the formula:
${\begin{cases}x=x_{0}+n{\frac {b}{\gcd(a,\;b)}}\\y=y_{0}-n{\frac {a}{\gcd(a,\;b)}}\end{cases}}\quad n\in \mathbb {Z} .$

Second, we need the first pair (x0,y0)
if
x=0
then
$y=(-12)$

Third, we gonna use that formula:
${\begin{cases}x=-n}\\y=-3(4+n)}\end{case}\quad n\in \mathbb {Z} .$
Congratulations! We solve it.

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3 years ago

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EleoNora [17]

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