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4 years ago

WHO WAS Tannatt William Edgeworth David

1 answer:

4 0

a Welsh Australian geologist and Antarctic explorer. A household name in his lifetime, David's most significant achievements were discovering the major Hunter Valley coalfield in New South Wales and leading the first expedition to reach the South Magnetic Pole. He also served with distinction in World War I.

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The mass number of an atom is determined by ___.

Reika [66]

2: protons and neutrons

3 0

3 years ago

Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.

aliina [53]

Answer:

x= 138.24 g

Explanation:

We use the avogradro's number

6.023 x 10^23 molecules -> 1 mol C2H8

26.02 x 10^23 molecules -> x

x= (26.02 x 10^23 molecules * 1 mol C2H8 )/6.023 x 10^23 molecules

x= 4.32 mol C2H8

1 mol C2H8 -> 32 g

4.32 mol C2H8 -> x

x= (4.32 mol C2H8 * 32 g)/ 1 mol C2H8

x= 138.24 g

4 0

4 years ago

What are solenoids......????

MrRissso [65]

Yo sup??

Solenoids are a kind of bar magnet.

The have low coercivity and low retentivity

The are made by taking a soft iron core and covering it with a coil.

Hope this helps.

6 0

3 years ago

Read 2 more answers

Consider the reaction 2 CO + O2 → 2 CO2 .What is the percent yield of carbon dioxide

Wewaii [24]

Answer:

$Y=50.9\%$

Explanation:

Hello,

In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}*\frac{44gCO_2}{1molCO_2} =15.7gCO_2$

Thus, as only 8 g were actually yielded, we compute the percent yield:

$Y=\frac{8g}{15.7g}*100\% \\\\Y=50.9\%$

Best regards.

7 0

3 years ago

How many moles of methane are in 7.31*10^25 molecules?

GrogVix [38]

<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Organic

Writing chemical compounds
Writing organic structures
Prefixes
Alkanes, Alkenes, Alkynes

Atomic Structure

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

Step 1: Define

7.31 × 10²⁵ molecules CH₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

121.388 mol CH₄ ≈ 121 mol CH₄

7 0

3 years ago