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mylen [45]
3 years ago
10

A certain compound is made up of two chlorine atoms, one carbon atom, and one oxygen atom. what is the chemical formula of this

compound? express your answer as a chemical formula.
Chemistry
2 answers:
Ostrovityanka [42]3 years ago
3 0
COCl₂  (phosgene)
_________________
hram777 [196]3 years ago
3 0

<u>Answer:</u> The chemical formula for the compound is COCl_2

<u>Explanation:</u>

A chemical compound which is formed by the combination of carbon, oxygen and chlorine atoms.

We are given:

Number of carbon atoms in the compound = 1

Number of oxygen atoms in the compound = 1

Number of chlorine atoms in the compound = 2

The chemical formula for the compound will be COCl_2. The chemical name for the given compound is phosgene.

Hence, the compound is COCl_2

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Which pair of elements will form a ionic bond
Marianna [84]

Answer:

Barium and Chlorine

Explanation:

Ionic bonds are formed between metals and non metals where the metals lose electrons and become positively charged and the non metals gain electrons and become negatively charge. The opposite charges cause them to be attracted to each other and Bond. The only metal in those options above is Barium. Therefore an ionic bond will be formed between Barium and Chlorine.

7 0
3 years ago
The materials or compounds that are changed into a new compounds in a chemical reaction are know as
OLga [1]

Answer:

Reactants

Explanation:

They become known as reactants

4 0
3 years ago
A chemist determines by measurements that 0.0200 moles of chlorine gas participate in a chemical reaction. Calculate the mass of
Schach [20]

Answer:

1.4200 g

Explanation:

The chlorine gas has a molecular formula Cl2. In table periodic, the molar mass of one atom of chlorine is 35.5 g/mol, so the molar mass of Cl2 is 71 g/mol.

Molar mass, mass and number of moles are related by the equation below:

n = \frac{m}{MM}

Where n is the number of moles, m is the mass, and MM is the molar mass of the compound.

So, for 0.0200 moles of Cl2 produced:

0.0200 = \frac{m}{71}

m = 71x0.0200

m = 1.4200

8 0
3 years ago
When 1.025 g of naphthalene (c10h8) burns in a bomb calorimeter, the temperature rises from 24.25°c to 32.33°c. find δerxn for t
Goryan [66]

Answer : The \Delta E for the combustion of naphthalene is 5161.25KJ/mole

Solution : Given,

Mass of naphthalene = 1.025 g

Initial temperature = 24.25^oC

Final temperature = 32.33^oC

Specific heat capacity of calorimeter = 5.11KJ/^oC

Molar mass of naphthalene = 128 g/mole

First, we have to calculate the heat absorbed, q

Formula used :

q=c\times \Delta T=c\times (T_{final}-T_{initial})

Now put all the given values in this formula, we get

q=(5.11KJ/^oC)\times (32.33^oCT-24.25^oC)=41.29KJ

Now we have to calculate the moles of naphthalene.

Moles of C_{10}H_{8} = \frac{\text{ Mass of }C_{10}H_{8}}{\text{ Molar mass of }C_{10}H_{8}}=\frac{1.025g}{128g/mole}=0.0080moles

Now we have to calculate the \Delta E for combustion of naphthalene.

\Delta E=\frac{q}{n}

where,

q = heat absorbed

n = number of moles

Now put all the values in this formula, we get

\Delta E=\frac{41.29KJ}{0.0080moles}=5161.25KJ/mole

Therefore, the \Delta E for the combustion of naphthalene is 5161.25KJ/mole

6 0
3 years ago
In the laboratory you dissolve 19.1 g of ammonium fluoride in a volumetric flask and add water to a total volume of 375 . mL. Wh
11111nata11111 [884]

Answer:

1.376 M

Explanation:

The following data were obtained from the question:

Mass of ammonium fluoride (NH₄F) = 19.1 g

Volume of solution = 375 mL

Molarity of ammonium fluoride (NH₄F) =?

Next, we shall convert 375 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

375 mL = 375 mL × 1 L / 1000 mL

375 mL = 0.375 L

Next, we shall determine the number of mole in 19.1 g of ammonium fluoride (NH₄F). This can be obtained as follow:

Mass of NH₄F = 19.1 g

Molar mass of NH₄F = 14 + (4×1) + 19

= 14 + 4 + 19

Molar mass of NH₄F = 37 g/mol

Mole of NH₄F =?

Mole = mass /Molar mass

Mole of NH₄F = 19.1 / 37

Mole of NH₄F = 0.516 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Volume of solution = 0.375 L

Mole of NH₄F = 0.516 mole

Molarity of NH₄F =?

Molarity = mole /Volume

Molarity of NH₄F = 0.516 / 0.375

Molarity of NH₄F = 1.376 M

Therefore, the molarity of the ammonium fluoride (NH₄F) is 1.376 M

3 0
3 years ago
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