Ch3ch2ch2ch2ch2ch3 Is called Hexane, it is a colorless liquid hydrocarbon
The new pressure, P₂ is 6000 atm.
<h3>Calculation:</h3>
Given,
P₁ = 1.5 atm
V₁ = 40 L = 40,000 mL
V₂ = 10 mL
To calculate,
P₂ =?
Boyle's law is applied here.
According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.
PV = constant
Therefore,
P₁V₁ = P₂V₂
Put the above values in the equation,
1.5 × 40,000 = P₂ × 10
P₂ = 1.5 × 4000
P₂ = 6000 atm
Therefore, the new pressure, P₂ is 6000 atm.
Learn more about Boyle's law here:
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When cohesive force is stronger than the adhesive force: concave up meniscus, water forms droplets on surface
Answer:
Volume of NaOH required = 3.61 L
Explanation:
H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:
--------(1)
where, Ka1 = 1.5 x 10–2 or pKa1 = 1.824
--------(2)
where, Ka2 = 1.0 x 10–7 or pKa2 = 7.000
The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.
Step 1:
Based on equation(1), at the first eq point:
moles of H2SO3 = moles of NaOH

Step 2:
For the second equivalence point setup an ICE table:

Initial 1.98 ? 0
Change -x -x x
Equil 1.98-x ?-x x
Here, ?-x =0 i.e. amount of OH- = x
Based on the Henderson buffer equation:
![pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles](https://tex.z-dn.net/?f=pH%20%3D%20pKa2%20%2B%20log%5Cfrac%7B%5BSO3%5D%5E%7B2-%7D%20%7D%7B%5BHSO3%5D%5E%7B-%7D%20%7D%20%5C%5C6.247%20%3D%207.00%20%2B%20log%5Cfrac%7Bx%7D%7B%281.98-x%29%7D%20%5C%5Cx%3D0.634%20moles)
Volume of NaOH required is:

Step 3:
Total volume of NaOH required = 3.22+0.389 =3.61 L
Explanation:
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